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说明：  贪心方法是一种改进了的分级处理方法。它首先根据题意，选取一种量度标准。然后按这种量度标准对这n个输入排序，并按排序一次输入一个量。如果这个输入和当前已构成在这种量度意义下的部分最优解加在一起不能产生一个可行解，则不把此解输入加到这部分解中。这种能够得到某种度量意义下的最优解的分级处理方法称为贪心方法。(greedy method is an improvement of the classification methods. According to its first title Italy, and a selection of standards of measurement. Then, under such a standard measure of this sort n input, with an input an order volume. If the input current and constitutes a measure of significance in this part of the optimal solution together not produce a feasible solution. this solution will not put this added to the importation of decomposition. This can be a meaningful measure of the optimal solution hierarchical method, known as greedy method.)

各种排序的模板实现，并分析了各种实现的时间复杂度及改进办法(Templates of various sort, and analyze the time complexity of the various implementations and ways to improve)

通过c语言数组算法解决josephus问题，m个人围成一圈，从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开，最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)

二叉树的链式存储、先序中序遍历和层次遍历。（构造一棵树并输入数据，编写三个函数，非别是树的前序递归遍历算法、树的后序递归遍历算法、树的非递归中序遍历算法（这里的非递归以中序为例）。在主程序中调用这三个函数进行树的遍历，观察用不同的遍历方法输出的数据的顺序和验证递归与非递归输出的数据是否一样。）(Chain store binary tree, preorder traversal and hierarchy traversal.)

遗传算法实现飞机在三维空间的航迹规划 C代码(Genetic Algorithm Route Planning C code)

c++数据结构中的二分查找树，是比较基本的数据查找结构，查找效率比较高(c++ data structure in the binary search tree, is a more basic data to find the structure to find more efficient)

本资料为数据结构的相关试卷，可以帮助大家解决一下有关考试的问题(This information is relevant papers data structure that can help you solve the problems concerning the examination)

1>实现可以随意浏览任一景点的介绍。（功能一） 2>可以给出任意两个景点的最短距离及其路线。（功能二） 3>可以查看任一景点热度，并可以对对所有景点热度（访问次数）进行排序。（功能三） 4>每个景点相关内容从文件读取，实现对文件操作的练习。 (1> implementations can feel free to browse introduce 任一景 points. (Function a) 2> You can give the shortest distance and route between any two attractions. (Function b) 3> You can view Renyi Jing point heat, and heat can all attractions (visits) to be sorted. (Function c) 4> each spot related content file reading, to achieve the file operations exercises.)

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)

此程序用于解决8皇后问题，运行后输出8皇后问题的所有解(This program is used to solve the 8 queens problem, all solutions of 8 queens problem output operation.)