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Matlab-mathematical-application
matlab 数学应用,讲解如何用matlab求数学极限,倒数,积分,微分等数学运算(Matlab mathematical application)
- 2012-03-28 21:05:21下载
- 积分:1
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eight
Audio signal modelling containing a sequence of 2 identical chirp signals with an addition to filtering an image using simple low-pass 1-D filter.
- 2014-02-12 16:48:27下载
- 积分:1
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DeSourceCode
差异演化算法的MATLAB程序,程序说明非常详尽,AI研究者必备(Differential evolution algorithm,
Matlab)
- 2010-01-21 10:34:24下载
- 积分:1
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I-Oout
说明: 输入输出,它是告诉我们具体在输入输出方面如何操作,是有效地资料(output input)
- 2010-04-18 20:28:21下载
- 积分:1
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sjwl
神经网络的matlab源码,可以运行,查看结果,非常棒(Neural network matlab source)
- 2012-11-19 20:57:16下载
- 积分:1
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利用禁忌搜索算法,解决基站选址问题Tabusearch
在MATLAB平台,实现利用禁忌搜索算法,解决基站选址问题(In the MATLAB platform, use the so called tabusearch algorithm to solve the problem of secleting the best base station locations)
- 2020-11-27 22:59:31下载
- 积分:1
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fenge30430
说明: 一些关于PCNN进行图像分割的Matlab程序,非常的好用.(PCNN for image segmentation about the Matlab program, very easy to use.)
- 2011-03-06 12:56:37下载
- 积分:1
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qpsk
本程序实现QPSK信号,通过瑞利信道后的各部分星座图(The program QPSK signal, Rayleigh channel through each part of the constellation after)
- 2021-04-28 20:18:43下载
- 积分:1
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Cymbal_V.P._Teorija_informacii_i_kodirovanie
Book theory of informatoin. It will be important for you.
- 2015-04-19 22:10:22下载
- 积分:1
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DCT_IDCT
to understand the Algorithm go to matlab help in page dct2 and idct2 to get the mathematical expression
for M = N = 8, we can calculate the most of hard values and save it as LUTs to speed up the execution
now compare our special 8X8 functions with the internal general functions
use this code:
A = int32(100*rand(8,8))
tic for i = 1 : 1000 IDCT_8X8(DCT_8X8(A)) end toc
tic for i = 1 : 1000 idct2(dct2(A)) end toc
i had built the general functions too, but with low speed (to understand the Algorithm go to matlab help in page dct2 and idct2 to get the mathematical expressionfor M = N = 8, we can calculate the most of hard values and save it as LUTs to speed up the executionnow compare our special 8X8 functions with the internal general functionsuse this code: A = int32 (100* rand (8,8)) tic for i = 1: 1000 IDCT_8X8 (DCT_8X8 (A)) end toc tic for i = 1: 1000 idct2 (dct2 (A)) end toc i had built the general functions too, but with low speed)
- 2007-12-05 18:28:42下载
- 积分:1