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shibiao

于 2016-10-17 发布 文件大小:2865KB
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下载积分: 1 下载次数: 14
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代码说明：

  水表数字识别主要对指针式水表进行数字识别(shui biao shu zi shibie)

文件列表：

水表指针识别(包含能够识别的图片)
................................\8BIT.cpp,1064,2010-01-10
................................\8BIT.h,1288,2009-11-19
................................\ChildFrm.cpp,1537,2008-09-24
................................\ChildFrm.h,1397,2010-01-10
................................\Debug
................................\.....\8BIT.obj,10864,2010-01-10
................................\.....\ChildFrm.obj,16153,2009-12-08
................................\.....\Dlg.obj,18274,2010-01-10
................................\.....\MainFrm.obj,20561,2015-10-24
................................\.....\StdAfx.obj,105607,2009-12-08
................................\.....\teach_test.exe,163894,2015-10-24
................................\.....\teach_test.ilk,441080,2015-10-24
................................\.....\teach_test.obj,28518,2009-12-09
................................\.....\teach_test.pch,5513416,2009-12-08
................................\.....\teach_test.pdb,566272,2015-10-24
................................\.....\teach_test.res,9932,2015-10-24
................................\.....\teach_testDoc.obj,23563,2010-01-10
................................\.....\teach_testView.obj,97772,2015-10-24
................................\.....\vc60.idb,254976,2015-10-24
................................\.....\vc60.pdb,380928,2015-10-24
................................\.....\ZFT.obj,9902,2009-12-09
................................\.....\ZFTDlg.obj,18880,2010-01-10
................................\.....\ZHIFT.obj,15238,2009-12-09
................................\Dlg.cpp,1551,2010-01-10
................................\Dlg.h,1356,2010-01-10
................................\MainFrm.cpp,2764,2015-10-24
................................\MainFrm.h,1570,2010-01-10
................................\ReadMe.txt,4874,2008-09-24
................................\res

................................\...\teach_test.rc2,402,2008-09-24


................................\resource.h,2543,2015-10-24
................................\StdAfx.cpp,212,2008-09-24
................................\StdAfx.h,1054,2008-09-24
................................\teach_test.aps,33600,2015-10-24
................................\teach_test.clw,5817,2015-10-24
................................\teach_test.cpp,5189,2008-09-24
................................\teach_test.dsp,5006,2010-01-10
................................\teach_test.dsw,543,2008-09-24
................................\teach_test.h,1484,2008-09-24
................................\teach_test.ncb,484352,2015-10-24
................................\teach_test.opt,620544,2015-10-24
................................\teach_test.plg,982,2015-10-24
................................\teach_test.rc,17338,2015-10-24
................................\teach_testDoc.cpp,7189,2010-01-10
................................\teach_testDoc.h,1944,2010-01-10
................................\teach_testView.cpp,34007,2010-01-10
................................\teach_testView.h,4194,2010-01-10
................................\ZFT.cpp,953,2009-12-07
................................\ZFT.h,1238,2009-12-09
................................\ZFTDlg.cpp,2443,2010-01-10
................................\ZFTDlg.h,1221,2010-01-10
................................\ZHIFT.cpp,2993,2009-12-09
................................\ZHIFT.h,1280,2009-12-09

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    E:Visual_C__MFC扩展编程实例 例18 动态地抓取应用程序的屏幕图像并将其打印。 上一个实例打印的是文档的报表，而不是当前出现在屏幕上的内容。在本例中，将实现 屏幕抓取并打印其内容。M F C 为打印视提供了有限的支持， 但只要用M F C 在 C Vi e w : : O n D r a w ( )中所提供的设备环境，就可以绘制自己的视。在打印视的时候， M F C只需调 用具备打印机设备环境的O n D r a w ( )函数即可。但是，如果不绘制自己的视，例如，用一个或 者一个以上的控件窗口填充自己的视就不会打印任何东西。每个控件将使用自己的设备环境 将自己打印到屏幕，因此打印视的唯一途径就是抓取屏幕(拷贝其内容到一个位图对象)并将其 打印到打印机。由于该功能整个与位图相关，因此将该功能封装到了位图类中。(E : Visual_C__MFC expand programming examples cases 18 crawls dynamic application's screen images and their Print. Print example, a document is a statement, rather than the current appeared on the screen content. In this case, to achieve the screen crawls and print its contents. M F C Print, as provided limited support, but as long as M F C in C Vi e w : : O r a n D. w (), which provided the equipment environment, we can draw our own consideration. In Print, as when M F C only with the printer device called the environment O D r a n w () function can be. However, if we do not draw their attention, for example, or one with a control over their windows filled as it will not print anything. Controls will use their own equipment to their environment to Print Screen, Therefore, as Print i)
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  • Gcode
    说明：  G代码生成软件，能准确生成数控机床的G代码(G code generation software to generate accurate numerical control machine tool G-code)
    2008-10-09 17:04:39下载
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  • zoj1094
    zoj094 Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. (Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. )
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    2016-02-07 11:02:08下载
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