KQSQDAJ

说明：  极化码极化信道仿真，信道极化是信道合并与信道分裂两种信道操作的结果。在上述两种操作下，原本相同的N个W信道产生了极化现象，其中一部分信道的信道容量趋近于1，另一部分信道的信道容量趋近于0。(Channel polarization is the result of channel merging and channel splitting. Under the above two operations, the original n w channels have polarization phenomenon. The channel capacity of one part of the channel approaches to 1, and the channel capacity of the other part approaches to 0.)

读取CORS数据，重采样成30秒，计算电离层总电子含量(Read CORS data, resampling into 30 seconds, calculate the total electron content of the ionosphere)

主要关于ofdma中资源分配动态分配的算法中的注水算法的介绍(it is about waterfilling allocation dynamic allocation of ofdma algorithm introduced)

天线相关性对MIMO系统BER性能的影响分析(Antenna MIMO system BER performance analysis)

this is simply a report on the fading channel on different modulation scheme

信道检错编码，CRC编码，包括详细的注释，很不错的程序(Channel error detection codes, CRC codes, including detailed notes, a very good program)

中兴手机v788d改cpn通过cpn改IMEI(change v788d cpn)

说明：  2. 关于无线信道的多普勒谱，请回答以下问题： (1) 在某些无线信道中，多普勒频移会引起无线信道输出信号的混叠。请描述产生混叠的各种原因； (2) 无线信道中的多普勒谱有一种经典谱(classic spectrum)，请解释产生这种谱形状的机理； (3) 请用Simulink工具编写代码(S-Function方式)，产生一单径瑞利信道，其多普勒谱为经典谱，其中移动速率为120km/h。并请描述：自己用计算机产生的经典谱是正确的依据。(2. Regarding the doppler spectrum of the wireless channel, please answer the following questions: (1) in some wireless channels, doppler frequency shift will cause aliasing of the output signals of the wireless channel.Describe the various causes of aliasing; (2) there is a classic spectrum in the doppler spectrum in the wireless channel, please explain the mechanism of producing this spectrum shape; (3) please use Simulink tool to write code (s-function mode) to generate a single-path Rayleigh channel, whose doppler spectrum is the classical spectrum, in which the moving rate is 120km/h.And please describe: your own computer generated classical spectrum is the correct basis.)

A simulator for wireless sensor networks using omnet ++ framework

说明：  Proteus 8051+LCD+PWM电机调速测速（仿真+源码）(Proteus 8051+LCD+PWM Motor speed measurement (simulation + source))