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很好,欢迎下载。2009年4月16日.很好,欢迎下载。很好,欢迎下载。...
很好,欢迎下载。2009年4月16日.很好,欢迎下载。很好,欢迎下载。-Well, welcome to download. April 16, 2009. Well, welcome to download. Well, welcome to download.
- 2022-04-30 20:17:22下载
- 积分:1
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Soma-Client-source-code
vc 2008 环境下编译 ,很早的游戏,圣者无敌客户端源码(Under vc 2008 compiler environment, Ancient game, soma client source code)
- 2021-04-09 14:58:59下载
- 积分:1
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生成对抗网络在mnist数据集上的源代码
生成对抗网络,亲测可用,带有说明,有利于初学者学习(Generate confrontation network, pro-test available, with instructions)
- 2021-03-24 15:39:14下载
- 积分:1
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一套完整的同学录静态页面程序,每工相当不错哦。
一套完整的同学录静态页面程序,每工相当不错哦。-a complete set of static website pages, each work is quite good, oh.
- 2023-04-18 02:00:04下载
- 积分:1
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The latest version V1.032 version of TCP/UDP debugging tools, modify the previou...
最新版本V1.032版本的TCP/UDP调试工具,修改了上一版本的bug,提供应用程序接口,帮助学习TCP/UDP协议栈,尤其对开发带有TCP/UDP接口的硬件设备很实用,相当于串口超级终端的功能(可以叫做网口超级终端!)-The latest version V1.032 version of TCP/UDP debugging tools, modify the previous version of one bug, to provide application programming interfaces to help learning TCP/UDP protocol stack, in particular on the development of a TCP/UDP interface hardware device is very useful, very in serial HyperTerminal function (can be called network HyperTerminal mouth!)
- 2022-06-30 03:27:57下载
- 积分:1
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matlab源程序及说明
关于捷联惯导与多普勒计程仪组合导航的算法程序,比较基础。方便初学者尝试(The algorithm program of SINS and Doppler Log integrated navigation is comparatively basic. Easy for beginners to try)
- 2020-07-01 08:00:02下载
- 积分:1
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套接字编程实例
Linux Socket Programming by Example
- 2022-01-30 23:03:45下载
- 积分:1
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SServer
这个demo是一个twain协议实现的demo(This demo is a demo implemented by Twain protocol)
- 2020-06-19 22:00:01下载
- 积分:1
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OPCServerDTools
opcserver开发包,带Visual C++源码例子。(opcserver development kit, with Visual C++ source code examples.)
- 2021-01-29 14:18:35下载
- 积分:1
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实验一
说明: 一般信道容量迭代算法
(1)初始化信源分布:P^((0))=(p_(1 ),p_(2 ),…,p_(i ),…,p_r),置迭代计数器k=0,设信道容量相对误差门限为δ,δ>0,可设C(0)=-∞;
(2)φ_ji^((k))=(p_ij p_i^((k)))/(∑p_ij p_i^((k)) ) i=1,…,r;j=1,…,s;
(3)p_i^((k+1) )=exp?[∑_j?〖p_ij lnφ_ji^((k)) 〗]/(∑_i?〖{exp?[∑_j?〖p_ij lnφ_ji^((k)) 〗]}〗) i=1,…,r;
(4)C^((k+1))=ln∑_i?〖{exp?[∑_j?〖p_ij lnφ_ji^((k)) 〗]}〗;
(5)如果,
(|C^((k+1) )-C^((k)) |)/C^((k+1)) ≤δ,
转向(7);
(6)否则,置迭代符合 k+1→k,转向(2);
(7)输出p_i^((k+1) )和C^((k+1));
(8)停止。(General channel capacity iterative algorithm)
- 2020-05-21 14:30:04下载
- 积分:1