CurrentControl

说明：  harris 角点检测的完整matlab程序 可直接运行(harris corner detection of the complete program can be run matlab)

本代码用于实现图片中的光照补偿，效果较好，实用性较强！(The code used for illumination compensation in the picture, better practicality!)

认知无线电资源分配的经典文章，有时间大家可以看一下，写的挺好的。(failed to translate)

电动汽车大量接入电网对电网负荷的影响（蒙特卡洛）(A large number of electric cars on the grid interconnection will affect the grid load (Monte Carlo))

基于最小二乘法展开法的定位程序 tdoa 减小误差(Reduce the error based on the locator expansion method tdoa the method of least squares)

代码图像以及matlab语言中函数的调用，保证运行结果(matlab )

粒子群算法程序，有重要参考价值，尤其适合初学者(particle swarm algorithm procedure, which has important reference value，particularly suitable for beginners )

单输入单输出的GPC的matlab实现,欢迎交流。(GPC SISO matlab implementation)

matlab 与VC混合编程 PDF格式 刘维编著 还算清晰，有兴趣的朋友下载下来看看(matlab Programming PDF format mixed with VC Liu Wei edited fairly clear, interested to see friends downloaded)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)