FFT_varying_h0

安卓人才企业面试题汇总，是从事安卓软件开发工作应聘时必要的宝典(Andrews personnel and enterprises face questions summary is engaged in the Android software development work necessary when candidates Collection)

说明：  介绍了FPGA的使用以及modelsim联合synplify工具的使用方法(This paper introduces the use of FPGA and the use of Modelsim joint Synplify tool)

程序目的： 输入一个任意大小的迷宫，用栈求出一条走出迷宫的路径，并 显示在屏幕上。 程序实现： 可以实现载入迷宫和保存迷宫，附带文件中有4个测试迷宫路径的 文件test1~4.dd。请将这些文件拷贝到TC当前目录下，或者在载 入时写明完全路径。由于屏幕大小的限制，当用户自己输入迷宫 时一定要注意：迷宫大小是有限制的，不小于4*3,不大于30*20。 否则会出现错误信息。输入开始时全是墙，用上下左右键移动， 用Del键删除墙，形成通路，用Enter键添加墙。输入结束时可以 将迷宫保存下来，以dd为扩展名。输入完毕时用F9键来得到结果， 找到路径时，屏幕下方会出现Path found，否则出现Path not found。 程序经Turbo C 2.0编译调试成功。运行时不用添加任何运行库。 不可以在VC上编译。-procedures purpose : to bring in a maze of arbitrary size, with a stack get out of the maze of trails and on the screen. Program : can achieve and preserve the printed maze maze, the accompanying documents were four test maze of trails to document test1 4.dd. I would be grateful if those files are copied to the TC current directory, or in the state when fully contained path. Due to restrictions on the size of the screen when the user input labyrinth must pay attention to : the size of the maze is a restriction, not less than 4* 3, not more than 30* 20. Otherwise there will be a wrong message. At the beginning of the importation of a

这是我自己编写的 c++builder60环境下的 一个小程序,主要体现了人工智能里的A*宽度优先搜索-This is my own c builder60 prepared by the environment of a small procedure, mainly embodies the artificial intelligence Lane width of the A* search priority

利用 485 总线，通过MODBUS 实现与PLC的通信，内容完整，测试通过(The c is STM32 of communictaion for PLC)

说明：  it is useless, i am sorry

一个雷达的模拟程序-a radar simulation program

用vrml编写，建立的一个比较精细的蜘蛛模型-Vrml by the development, set up a more sophisticated model of the spider

matlab人员疏散，供大家参考使用，可以根据需要修改。(MATLAB code for evacuation. You can change it based on your needs.)

说明：  普通轿车，主动悬架模型，鲁棒控制，提高舒适性(traditional vehicle, active suspension model, robust control, improve comfort)