matalab-多重分形谱算法+盒子维数的计算

玉儿无神地呆在办公室,她不想回家,她象受到重创般再没有以往的神气,就在她正享受这份孤独寂寞时,刺耳的短信...刚刚发了一篇作品,一种好奇心的驱使,她误闯进了一家聊天室,其实也就是联想总站的一个小聊天室而已-Erh startling to stay in office, she does not want to go home, as she has been hard hit as no previous listless, She is on the enjoyment of this loneliness, piercing SMS ... has just made a one works, a curiosity, She had mistakenly entered a chat room, in fact, is the terminus of an association of small chat room only

说明：  彩色TFT液晶显示控制电路设计及其ASIC实现(TFT color LCD control circuit design and ASIC realization)

用 cocos2d-x 3.4 开发的俄罗斯方块(Use cocos2d-x 3.4 development game tetris)

Use of Genetic Algorithm for the travelling sales man problem

用ASP做的许愿墙壁。很好玩的一个东西。希望大家会喜欢。-ASP Wishing to do the walls. A very fun thing. I hope you will like.

四轴无人机的飞控源代码含有中文注释以及可以写入单片机的hex文件(Flight control source code for four-axis drone)

智能优化算法及其在机械工程中的应用，该书介绍最新群体智能算法在机械工程的应用(Intelligent optimization algorithm and its application in mechanical engineering, the book describes the latest swarm intelligence algorithm in mechanical engineering applications)

说明：  Background Given a set of rectangles {R1, R2, …, Rn}, compute the area of their common intersection. i.e., Area(R1∩R2∩…∩Rn) The edges of the rectangles R1, R2, …, Rn, are either vertical or horizontal lines. For example, the intersection of 4 rectangles, R1, R2, R3, and R4, in the following figure is the shaded rectangle. Input The input contains (N + 1) lines. The first line specifies the number of rectangles N, where 1 < N < 1000. Since the sides of the rectangles are parallel to the x-axis and y-axis, each rectangle is bounded by the lines x = x1, x = x2, y = y1 and y = y2 and each subsequent line of the input file thus specifies one rectangle in the following format: x1 x2 y1 y2 such that 0 <= x1 < x2 <= 10000 and 0 <= y1 < y2 <= 10000, and x1, x2, y1 and y2 are integers. Output The output file contains the area of the intersection of all the rectangles.

说明：  用python语言实现了井字游戏，代码含注释，简单易懂(Well word game realized)

类似于资源管理器的程序,可以查看,系统的所有资源,不错(Similar to the resource manager application, you can view, all the resources in the system, good)