损伤单位算法

c++实现的静态链表 可以从屏幕输入来构建静态链表 数据结构重要的部分(c++ implemented statically linked list can be input from the screen to the important part to build a static linked list data structure)

数据结构中单链表的源代码，该程序可以实现单链表的插入，删除，查找等基本功能-this program is very good

经过改进的C语言位操作功能-improved C-language feature

数据结构双链表的 例子-data structure-Chain example

某公司收到若干报价，然后报价由低到高进行排序。设最低报价为F,最高报价为G。n=0.2*(G-F) 设A，B，C，D，E五个等距区间并取： A=[F,F+n） B=[F+n,F+2n) C=[F+2n,F+3n) D=[F+3n,F+4n) E=[F+4n,G) 所有的报价都按各自的大小，分别列入上面五个区间。各自区间内的最小报价为该区间的代表报价。如果某区间内没有报价 则以小于该区间的且与该区间相邻的区间内的最高报价代表该区间报价，如果该区间与与之相邻的较小区间内都没有报价则该区间不参加最后计算。取各区间的代表值， 求出其平均值 做为评标基准报价 (A company received a number of quotations, and quotations from low to high order. Minimum price for the F, the highest offer for the G. n = 0.2* (GF) Let A, B, C, D, E, and five equidistant intervals obtained: A = [F, F+ n) B = [F+ n, F+2 n) C = [F+ 2n, F+3 n) D = [F+3 n, F+4 n) E = [F+4 n, G) All quotes are by their size, five were included in the above range. The minimum offer their own range representative of the range quoted. If a range does not offer less than the range of places and range of adjacent intervals with the highest offer within the offer on behalf of the interval, if the interval and the adjacent smaller range do not offer the range not to participate the final calculation. Take the representative value of each interval, calculate the average price as a benchmark evaluation)

迷宫算法（maze） /* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK, * 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary. * Each step can be made horizontally or vertically for one more grid (diagonal * jump is not allowed). * Your program should print a series of grid coordinates that start from m[0][0] * and go to m[9][9] * Hint: No need to find the shortest path, only need to find one path that gets * you to desitination. */ -/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK, * 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary. * Each step can be made horizontally or vertically for one more grid (diagonal * jump is not allowed). * Your program should print a series of grid coordinates that start from m[0][0] * and go to m[9][9] * Hint: No need to find the shortest path, only need to find one path that gets * you to desitination.

Visual+C+++6.0数据库开发技术与工程实践（下），共7个实例，有源代码，使用前看光盘使用说明-Visual+ C+++6.0 database development Technology and Engineering Practice (below), a total of seven instances, active code, CD-ROM read instructions before use

DAO读写-literacy DAO

vb实现的排序算法演示vb实现的排序算法演示.冒泡、选择、折半等多种排序算法(vb sort demodemodemodemodemovb sort demodemodemodemodemo)

数据结构中的几种基本结构的C++实现：栈、队列、链表-data structure of several basic structure of the C achieved : Stack, Queue, Listless