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signal
产生2fsk或4fsk的调制信号,可以控制带宽,中心频率,噪声,可以观察频谱(this can product signal)
- 2010-05-06 14:59:29下载
- 积分:1
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SPWM-voltage-invertor
:SPWM调制技术是通过改变输出方波的占空比来改变等效的输出电压,其调制波为正弦波,脉冲宽度间占空
比按正弦规率排列, 这样输出波形经过适当的滤波可以做到正弦波输出。它广泛的用于支流交流逆变器。本次实
验使用Matlab/Simulink对SPWM技术进行仿真并分析数据。(: SPWM modulation by changing the duty cycle square wave output to change the equivalent output voltage, the modulated sine wave, pulse width, duty cycle between the rate at sine arranged so that the filter output waveform can be done properly to the sine wave output. It is widely used in branch AC inverter. The experiment uses Matlab/Simulink simulation of the SPWM technique and analyze data.)
- 2011-05-22 15:03:05下载
- 积分:1
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FCSmodel(book)
燃料电池的simulink模型,该燃料电池的原型为Ballard Mark-700,75kw(fuel cell simulink model )
- 2021-02-21 21:19:42下载
- 积分:1
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DEEC1VSDEEC2
用matlab语言实现无线传感器网络LEACH算法,和其改进算法。并比较改进算法的优点。(Matlab language implementation wireless sensor network LEACH algorithm, and the improved algorithm and compare the advantages of the improved algorithm)
- 2012-04-19 19:55:17下载
- 积分:1
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UWBBPSK
这个文档采用BPSK超宽带系统。接收器是一个相关接收机具有集成低通滤波器和比较器的门限的选择(This m file models an UWB system using BPSK. The receiver is a correlation receiver with a LPF integrator and comparators for threshhold selection)
- 2014-08-08 17:13:13下载
- 积分:1
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jytz.m
求取倒频谱系数,可对声音信号进行分析,是一种特征提取方式(Obtaining cepstral coefficients, can the sound signal analysis, feature extraction is a way)
- 2016-06-22 18:02:08下载
- 积分:1
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MATLAB1
学习MATLAB数值分析,能够利用MATLAB进行曲线拟合、插值以及解高阶方程等等(Learning MATLAB Numerical Analysis)
- 2009-10-17 20:23:42下载
- 积分:1
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wavepack
这时一些关于matlab连续小波变换的程序代码,希望对学习matlab的人有用处(At this time about the continuous wavelet transform matlab code, people who want to learn useful matlab)
- 2010-12-24 14:13:55下载
- 积分:1
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linearpll
说明: 一个不错的PLL matlab simulink 仿真,希望能帮到你(A good PLL matlab simulink simulation, hope you can help)
- 2011-03-23 22:48:37下载
- 积分:1
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we
说明: 七单元天线阵DOA估计
clear clc
d=1 天线阵元的间距
lma=2 信号中心波长
q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向
A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子
A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)]
A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)]
A4=[exp(-2*pi*j*d*[0:6]*cos(q4)/lma)]
A=[A1,A2,A3,A4] 得出A矩阵
n=1:1900
v1=.015 四信号的频率
v2=.05
v3=.02
v4=.035
d=[1.3*cos(v1*n) 1*sin(v2(we)
- 2010-05-06 15:26:50下载
- 积分:1