高校学籍管理问题设计方案

复制 测量长度 比较 等函数的 书写 还有 一些其他函数的书写 都是c++课程老师布置的作业(Copy measuring the length of comparison function of writing, there are some other functions of writing are c++ course teacher assignments)

VB语音报数计算器源程序,有需要的就下载吧。(Talking Calculator VB source code, there is a need to download it.)

A book that explains tool Ms Flex Grid in visual Basic 6

Rigol osciloscope tool

另外的一个潮流计算程序，仍是采用直流潮流法(Another trend of the computer program is still using DC power flow)

对地址薄的初学测试,自己写的,希望对大家有所启发吧(Address book for novice test, write your own, we hope to inspire it)

实现高斯滤波等功能，适合VC初学者，可通过代码了解滤波原理。(Gaussian filter functions for VC beginners, filtering through the code to understand the principle.)

mini cortez mybusiness pos v11

西南交通大学ACM 1075题解源码，C++编写，保证能够AC(Southwest Jiaotong University, ACM 1075 to a problem source, C++ written guarantee that AC)

VC++枣子穿纽游戏源码，类似扫雷游戏的界面，不过玩法有点不一样，游戏源代码在vc++6下编译通过，你应该通过源代码能看出些玩法来。 　　相关资料：在本游戏中，你将作为一名裁缝，将尽可能多的纽扣穿成一个闭合的路线。游戏初始有 15 个纽扣，随着时间的增加，纽扣数目也增加，当达到70个时游戏即结束。只能在有纽扣的点穿线，且只能在水平方向或竖直方向穿线。线可交叉，但有纽扣的点不能交叉连接。 　　透露点秘诀：要尽可能使连线长且该连线上的纽扣数多。(VC++ source code dates to wear new game, the game interface similar to mine, but a bit different from playing the game in the source code to compile under vc++6 passed through the source code you should be able to see more options. Relevant information: in this game, you will serve as a tailor, will be wearing buttons as much as possible into a closed line. Game initial 15 buttons, an increase over time, increase the number of buttons, when the 70 hours to reach the end of the game that is. Buttons can only point in the threading, and only in the horizontal direction or vertical direction of threading. Lines cross, but the buttons can not be cross-connect point. Point revealed the secret: To the extent possible, so long and the connection to connect on a few more buttons.)