mouseMenu

说明：  画64*64达曼光栅，挺有意思的，可以试试(Draw 64 * 64 Dammann grating)

哲学家进餐问题，进程是独立参与分配资源的最小单位，在有线程的OS中，线程是运行的最小单位， 课堂所述进程之间的同步与互斥，实际上是属于不同进程的线程间的同步与互斥，当 然，属于同一进程的不同线程一样存在同步与互斥，其控制同步与互斥的原理跟进程 是一样的-dining philosophers problem, the process is independent participation in the allocation of resources as the smallest unit, in the OS thread, thread is the smallest unit of operation, the process described in the classroom between the synchronization and mutual exclusion. actually belong to different threads in the process of synchronization and mutual exclusion, of course, the same process there is a different thread synchronization and mutual exclusion, control and coordinate the process with the principle of the same

用java的acm库做的一个弹跳球的小游戏，适合初学者(The acm library with java to do a bouncing ball game, suitable for beginners)

这个是sap讲义，帮助大家认识sap有哪些方面业务知识。-This is a sap handouts to help everyone understand the sap has what knowledge.

这是我做的数据采集实验，通过AD采集数据，DA口输出模拟电压值-This is what I do experimental data acquisition, through the AD data acquisition, DA analog output voltage value

说明：  用Matlab实现钢琴演奏卡农，运行matlabpiano.m即可(MATLAB Playing Canon)

计算钢筋混凝土梁弯矩曲率关系，并输出钢筋混凝土梁弯矩关系图(calucate the M-u relationship of reinforecd concrete structure)

说明：  介绍了DUET盲源分离方法，可以仅使用两个混合信号分离任何数目的源分离方法。该 方法适用于源信号W-不相交正交的情况。(T the DUET Blind Source Separation method which can separate any number of sources using only two mixtures. The method is valid when sources are W-disjoint orthogonal, that is, when the supports of the windowed Fourier transform of the signals in the mixture are disjoint.)

说明：  stm32f103输入捕获测量方波频率和占空比的程序(Input acquisition frequency duty cycle)

一个弹窗选择人员，或者其他什么的通用组件(A popover selector, or some other generic component)