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abaqus-umat-good
abaqus umat for concrete constitive law
- 2021-05-08 13:58:36下载
- 积分：1
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计算器
说明： 计算器小程序 简易的计算器代码 自学练习 python 代码程序(Self-learning Calculator Small Program Learning)
- 2020-06-18 20:40:01下载
- 积分：1
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thank you for using this software,which is fugai method,when you can t catch it,...
thank you for using this software,which is fugai method,when you can t catch it,please ask me for my help!
- 2023-09-03 02:30:03下载
- 积分：1
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实现跳远运动员成绩的动态排序。每次一名运动员成绩出来，都会更新一次排名...
实现跳远运动员成绩的动态排序。每次一名运动员成绩出来，都会更新一次排名-Long jump athletes to achieve a dynamic sort. Every time an athletes out, will be updated every position
- 2023-03-04 07:20:03下载
- 积分：1
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上传pudn
从心电信号提取呼吸信号，和信号频谱分析
用于对信号的频谱分布做分析，输出为频谱变量和图示(Signal processing, signal spectrum analysis, signal energy
It is used to analyze the spectrum distribution of the signal, and output it as spectrum variable and icon.)
- 2018-08-28 16:37:35下载
- 积分：1
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PID_Ctrl
说明： PID控制模型，可用于代码生成及模型开发(PID proportional-integral-derivative control)
- 2020-07-01 18:40:02下载
- 积分：1
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三个野人和三个传教士要过河。
(1). 有三个野人和三个传教士要过河。
(2).只有一条船过河，船上每次只能座最多两个人。
(3).任何时候，野人的...
三个野人和三个传教士要过河。
(1). 有三个野人和三个传教士要过河。
(2).只有一条船过河，船上每次只能座最多两个人。
(3).任何时候，野人的数量不能比传教士多。否则野人就要吃了传教士。
(4).最终三个野人和三个传教士都要过到河的对面。
-Three Savage and three missionaries must cross the river. (1). There are three wild man and three missionaries must cross the river. (2). There is only one boat to cross the river, each boat can only seat a maximum of two people. (3). Any time the number of savages should not more than the missionaries. Otherwise, we should eat missionary Savage. (4). The final three Savage and three missionaries must cross the river opposite.
- 2022-05-16 02:03:15下载
- 积分：1
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const
说明： const 声明将常量放入符号表中，当const使用了extern或&符号，编译分配存储空间(The const declaration places constants in the symbol table, and when const uses extern or symbol, compiles and allocates storage space)
- 2020-06-24 23:40:12下载
- 积分：1
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Maze Find a path through the maze to any space character in the perimeter of the...
走迷宫 Find a path through the maze to any space character in the perimeter of the maze. Paths through the maze are denoted by a space character and walls by any other non white-space character (apart from . characters). -Maze Find a path through the maze to any space character in the perimeter of the maze. Paths through the maze are denoted by a space character and walls by any other non white-space character (apart from. Characters).
- 2022-12-29 19:05:03下载
- 积分：1
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load
广义互相关时延估计算法和最大互相关系数的取值(The value of generalized cross correlation time delay estimation algorithm and maximum correlation number)
- 2018-04-19 11:01:26下载
- 积分：1
