json-c-0.12.1-nodoc.tar

LED快速开发入门，LED接口调用协议。(LED AA bb cc dd eee fff gggg kkkk ccc)

boost asio网络编程入门教程，可以作为学习参考(Boost ASIO network programming introductory course, as a learning reference)

说明：  计算内弹道，固体火箭发动机装药内弹道计算(Calculating interior trajectory, solid rocket motor charge interior trajectory calculation)

说明：  目前我们的生活中到处都有基于ARM架构的芯片，移动互联网时代到来之后，尤其在智能手机领域，ARM可以说是处于统治地位，其他的类似平板电脑以及安卓设备等也都在采用ARM架构。 不过虽然ARM应用这么广泛，但是相关教材却比较少，让很多爱好者学习比较困难，而《ARM汇编语言官方手册》这本官方手册的发布给正在研究ARM汇编的人们提供了很大的帮助。文末有《ARM汇编语言官方手册》pdf免费资源分享，欢迎大家下载学习。 《ARM汇编语言官方手册》一共分为7个章节，不仅详细介绍了ARM的体系结构，还对汇编语言模块进行了深入的探究。手册中整理了绝大部分汇编中可能遇到的语法格式问题和ARM指令，给从业者研究ARM带来了很大的便利。 如果你想要赶上万物智联和人工智能的风潮并加入其中，那ARM绝对不可错过，现在文末免费分享《ARM汇编语言官方手册》PDF版本，欢迎下载学习。(At present, there are chips based on ARM architecture everywhere in our life. After the arrival of the mobile Internet era, especially in the field of smart phones, arm can be said to be in the dominant position. Other similar tablet computers and Android devices are also using ARM architecture. However, although arm is widely used, there are few related teaching materials, which makes it difficult for many lovers to learn. The official Manual of arm assembly language provides great help for people who are studying arm assembly language. At the end of the article, there is "arm assembly language official manual" PDF free resource sharing, welcome to download and learn.)

模糊综合评判算法，C程序，4个评价集，6个评价因子，欢迎下载(fuzzy comprehensive evaluation algorithm, C procedures, evaluation of four sets, six evaluation factor welcome Download)

与NJ系列PLC通讯上位机软件给予指令位置，与PLC 通讯并发送位置指令，伺服电机为负载(Communication with NJ series PLC upper computer software gives instruction position, communicates with PLC and sends position instruction. Servo motor is the load.)

激光小车引脚请自行修改我靠 还要我写多少字？(Laser trolley pin please modify how much I rely want me to write the word?)

DataTable与List集合之间转换类(Conversion classes between tables and List collections)

处理器调度算法代码的实现，简单易懂。非常棒的代码处理器跳读(this is saw your name in Penfriends magazines,and l would like to be your penfriend.First,l will tell you something about myself.My name is Jonathan Chen)

1-100之间有多少个素数，并输出所有素数及素数的个数。 ???? 程序分析：判断素数的方法：用一个数分别去除2到sqrt(这个数)，如果能被整除，则表明此数不是素数，反之是素数。(How many prime numbers are there between 1-100 and output all prime numbers and prime numbers. The method of judging prime number: 2 to sqrt (this number) is removed by one number, and if it can be divided, the number is not prime, and vice versa.)