登录
首页 » Visual C++ » 62

62

于 2017-04-19 发布 文件大小:14KB
0 313
下载积分: 1 下载次数: 3

代码说明:

说明:  大灰狼远程控制系统高仿8.62小马白加黑源码!过启动/过网购/过拦截/无提示上线(The Wolf remote control system of high imitation 8.62 pony white and black source! Before to start/shopping/interception/no tips online)

文件列表:

ServerDat
.........\decode.h,2231,2015-05-23
.........\MemoryModule.cpp,12639,2017-04-17
.........\MemoryModule.h,366,2014-09-17
.........\ReadMe.txt,1631,2017-04-17
.........\Release
.........\.......\DHL2013.exp,742,2017-04-17
.........\.......\DHL2013.lib,2238,2017-04-17
.........\ServerDat.cpp,10530,2017-04-17
.........\ServerDat.dsp,3144,2017-04-17
.........\ServerDat.dsw,524,2017-04-17
.........\ServerDat.plg,1379,2017-04-17
.........\StdAfx.cpp,296,2017-04-17
.........\StdAfx.h,802,2017-04-17
.........\删除临时文件.bat,416,2013-06-16

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • code1
    代码去注释,C++描述,趋势科技2011笔试题,修改网上一些版本的代码错误(Code to comments, C++ description, Trend Micro 2011 pen questions, modified version of the code line number of error)
    2010-11-29 20:56:10下载
    积分:1
  • medo
    设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组,每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n(n<=200),表示每个数组有n个数。接下来的两行分别是X,Y数组的元素。结果输出 程序运行结束时,将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
    2021-03-22 16:29:16下载
    积分:1
  • AdoCtrlAccess
    vc ADO控制Access数据库的程序源码,很不错的demo(vc ADO Access database program source code control, very good demo)
    2011-05-29 11:10:28下载
    积分:1
  • UsrExcelCreate
    VC++ 创建excel文件 内涵基本的方法,适合初学者(VC++ create excel file)
    2010-11-08 11:47:31下载
    积分:1
  • DSPLIT.DSW2
    灰度变换,非0元素取1法,固定阀值法,双固定阀值法,反色变换处理,窗口变换处理(gray transform, 0-element method for a fixed threshold, two fixed threshold, anti-color transformation, transform window)
    2007-01-26 18:46:02下载
    积分:1
  • JavaLauncher_EKA2
    this file is used to activate app on startup of nokia mobile.
    2013-09-05 14:50:11下载
    积分:1
  • MotionDetect
    说明:  移动侦测技术的设计与实现,包括移动侦测的原理和功能实现。(Motion detection technology, design and implementation, including the principle of motion detection and functional implementation.)
    2011-04-11 13:24:41下载
    积分:1
  • fenyou
    现有8升、5升、3升的容器各一个,均无任何度量标记,其中8升的容器装满油,其他两个为空。要求用上述容器倒来倒去,分成两份4升的油。(内附实验报告)(Existing eight liters, 5 liters, each a 3-liter container, no any measure mark, eight liter container filled with oil, the other two are empty. Requirements for the container shuffling back and forth, divided into two four liters of oil.)
    2015-11-15 17:54:53下载
    积分:1
  • Oakland
    点云数据集,用于点云数据的学习实验,wrl格式,可以用meshlab软件打开使用(Point cloud data set for point cloud data learning experiment, wrl format that can be opened using software with meshlab)
    2016-06-23 15:16:27下载
    积分:1
  • PTZ-camera-control-system
    使用vc++开发的云台镜头控制系统,主要通过串口实现控制,已编译通过,可学习使用(PTZ camera control system)
    2013-09-24 22:31:17下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载