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FDTD仿真二维圆柱隐身衣，附理论推导和matlab程序 二维TM波（Hx Hy Ez），传的是TE波的程序其实道理是一样的。边界采用UPML，平面波靠总场/散射场引入(Two-dimensional TM wave (Hx Hy Ez), TE wave transmission is in fact the procedure is the same reason. Boundary using UPML, a plane wave by the total field/scattered field into )

psk技术实现，并有详细的程序，有助于通信软件的开发(psk technology, and the detailed procedures, contribute to the development of communications software)

维也纳大学的LTE链路级仿真平台,实现了LTE两路及仿真的整个个过程(LTE link lever simulation)

说明：  matlab的应用，我搜集来的，对学matlab挺有用的。(matlab application, I come to collect, to learn matlab Tingyou use.)

此源代码,是一个非常适合研究与学习用的电力系统仿真软件源码，是一种基于mattlab的，有非常好的界面、仿真库等等，能进行PF、CPF、OPF等一些计算。 (This source code is a very suitable for research and study used in power system simulation software source code is a matlab-based, and has very nice interface, the simulation database and so on, can P )

基于Matlab软件读取GPS标准格式Rinex文件的新方法基于Matlab软件读取GPS标准格式Rinex文件的新方法(A new method to read the GPS standard Matlab software-based file format Rinex)

Multi-shift CGLS solves the systems of linear equations (A *A+TAU(I)*EYE(N))*X(:,I)=A *B (I=1:L) for X with the multishift CGLS algorithm. The right hand side (column) vector B must have length M, where the coefficient matrix A is M-by-N. TAU is a vector of reals (the shifts) of length L. For a short demo run main.m

利用网络实现函数逼近 使用的主要函数如下： NEWRB——设计径向基函数神经网络 SIM——对径向基函数网络进行仿真(Function approximation using the Internet to achieve the main function is as follows: NEWRB- the design of radial basis function neural network SIM- for radial basis function network simulation)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

Digital image watermarking using dct svd on color image