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应用禁忌搜索算法解决0-1背包问题

于 2020-11-17 发布 文件大小:83KB
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代码说明:

  利用禁忌搜索算法求解0-1背包问题。禁忌搜索算法相比其他搜索算法更优,设置藐视规则来避免陷入局部最优解。(Solve 0-1 Knapsack Problem based on Tabu search. The tabu search algorithm is superior to other search algorithms and sets contempt rules to avoid falling into local optimal solutions.)

文件列表:

030120642_陈洪杰_作业2\0-1背包禁忌搜索编程报告.doc, 118272 , 2012-12-14
030120642_陈洪杰_作业2\main.asv, 1426 , 2012-12-14
030120642_陈洪杰_作业2\main.m, 1493 , 2012-12-22
030120642_陈洪杰_作业2\near.asv, 804 , 2012-12-14
030120642_陈洪杰_作业2\near.m, 819 , 2012-12-14
030120642_陈洪杰_作业2\newlist.asv, 204 , 2012-12-14
030120642_陈洪杰_作业2\newlist.m, 204 , 2012-12-14
030120642_陈洪杰_作业2, 0 , 2012-12-14

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    输入信号的时域和频谱分析 输入信号为ft=[5cos(600*pi*t)+4cos(90*pi*t)+9]/18 输入信号为高频和低频信号的叠加:高频300Hz,低频45Hz( Of the input signal in time domain and spectral analysis of the input signal is ft = [5cos (600* pi* t)+4 cos (90* pi* t)+9]/18 input signal for the high-frequency and low frequency signal superimposed: frequency 300Hz, 45Hz low frequency)
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