-
Project2
实现通讯,以太网和欧姆龙plc之间通过网线进行通讯,很好很强大(To achieve communication, Ethernet and OMRON PLC through the network line to communicate, very good and powerful)
- 2020-06-20 06:00:01下载
- 积分:1
-
伙伴系统
伙伴系统的一些基本功能实现
包含分配内存函数及回收操作(Some basic functions of the buddy system are implemented.
Contains allocated memory functions and recovery operations.)
- 2017-10-08 14:18:54下载
- 积分:1
-
small arithmetic calculators
小型加减乘除计算器-small arithmetic calculators
- 2022-01-26 06:15:19下载
- 积分:1
-
plane_strain_pipe_start
Files for an analysis of plain stress in a pipe using ANSYS
- 2017-07-06 01:58:28下载
- 积分:1
-
51例程
说明: 陀螺仪数据读取,通过串口进行数据读取...(Gyroscope data reading)
- 2019-06-05 12:23:59下载
- 积分:1
-
VC++ Windows扩展名查询及说明程序
VC++ Windows扩展名查询及说明程序,为什么说是说明程序呢?因为查询出扩展名后,会有该扩展名文件类型的说明,用什么程序打开。另外这个查询程序还有一个亮点就是输入提示功能,当你输入任意字符的时候,若有匹配的扩展名,则会在输入框下边显示对应的扩展名类型及说明。
- 2022-02-25 10:39:13下载
- 积分:1
-
Delphi毕业论文:分布式多层数据库图书管理系统
Delphi毕业论文:分布式多层数据库图书管理系统,通过开发一个分布式多层数据库图书管理系统,学习用delphi开发分布式多层数据库系统。采用Delphi6.0和MS Server2000等软件为开发工具;通过对计算机硬件和软件解决方案的论证;对应用领域进行调查分析;参考各种资料和进行数据库编程实践。在指导老师的帮助下,已经基本上成功地实现了设计任务书的要求。使得设计的数据库系统能够实现一般数据库的管理。我们研究了数据库的查询优化问题。
- 2022-08-19 10:40:41下载
- 积分:1
-
lssy3
说明: Typical case management: Manage customer case content
Legal consulting management: users publish online consulting details, background view, management and other related operations
Web AD management: includes some image AD management. Generate JS calls, add couplets AD management and floating ads, can control whether to display (off), very powerful function
- 2020-11-23 19:30:05下载
- 积分:1
-
解决以下问题:
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分:1
-
aodv96
说明: AODV路由协议96版,使用Ubuntu平台实现(AODV routing protocol version 96, using the Ubuntu platform)
- 2021-01-04 16:51:10下载
- 积分:1