hosa

温度传感器芯片18B20的操作代码，都是经过验证正在使用的-18B20-chip temperature sensor operation code, are being used to verify

ex9_1 脉冲信号调制 ex9_2 载波10MHz，带宽2MHz的线性调频信号及其频谱图 ex9_3 产生7位巴克码编码的二相码 ex9_4 产生7位巴克码和线性调频的混合调制信号 ex9_5 瑞利分布实现程序 ex9_6 瑞利分布＋杂波 ex9_7 相关对数正态分布杂波 ex9_8 相关weibull分布杂波 ex9_9 相干相关K分布杂波 ex9_10 线性调频信号的数字化正交解调 ex9_11 雷达脉冲压缩处理 ex9_12 二相编码信号的脉压处理 ex9_13 用FFT和FIR方法实现MTD处理 ex9_14 雷达的恒虚警处理（CFAR） ex9_15 比较相参积累和非相参积累(ex9_1 pulse signal modulation ex9_2 carrier 10MHz, bandwidth of 2MHz and the linear frequency modulation signal frequency spectrum 7 Barker ex9_3 produce the two-phase coding code 7 Barker ex9_4 generated code and linear FM modulation of the mixed signal Rayleigh distribution ex9_5 implementation procedures Rayleigh distribution ex9_6+ Clutter lognormal distribution ex9_7 related clutter weibull distribution ex9_8 related clutter Related ex9_9 coherent K distributed clutter LFM signal ex9_10 digital quadrature demodulation radar pulse compression ex9_11 treatment ex9_12 BPSK signal pulse pressure treatment ex9_13 Ways to use FFT and FIR implementation deal with MTD ex9_14 CFAR radar deal (CFAR) Comparison ex9_15 coherent and noncoherent)

哲学家就餐问题是由Dijkatra提出并解决的典型同步问题。该问题描述的是有五个哲学家共用一张圆桌，分别坐在周围的五张椅子上，圆桌上有五个碗和五只筷子，他们的生活方式是交替的进行思考和就餐。平时，一个哲学家进行思考，饥饿时便试图取用其左右最靠近他的筷子，只有在他拿到两只筷子时才能进餐。进餐完，放下筷子继续思考。-Dining philosophers problem is presented and solved Dijkatra typical synchronization problems. Description of the problem is that there are five philosophers share a round-table were sitting around the five chair, round table has five bowl and five chopsticks, their way of life is the turn of thinking and eating. Normally, a philosopher to think, hunger when trying to access their nearest him about the chopsticks, only if he can get two chopsticks when eating. End meals, to lay down their chopsticks to continue thinking.

个人收集的一些引导程序-personal collection of some boot

用汇编实现两浮点数相乘，已经经过验证，可以运行实现，提供参考。。(Assembly to achieve two floating-point multiplies, has been verified, you can run to achieve, to provide a reference. .)

输入三个整数x,y,z，请把这三个数由小到大输出。 1.程序分析：我们想办法把最小的数放到x上，先将x与y进行比较，如果x>y则将x与y的值进行交换，然后再用x与z进行比较，如果x>z则将x与z的值进行交换，这样能使x最小。-Enter the three integers x, y, z, please these three the number of small to large output. 1. Program analysis: We think of a way to put x number of the smallest, the first comparison of x and y, if x> y will be the value of x and y exchange and then to compare x and z, if x > z will be x and z values of the exchange, which will enable x minimum.

这是个 MASM 的 编译环境，可以帮助大家来编写汇编语言，早期的版本-This is a MASM compiler environment, can help you to write assembly language, early version

数字电子钟 汇编程序，数字电子钟汇编程序 单片机-Digital electronic clock assembler, digital electronic clock assembler Singlechip

编程高手 讨论 -programming experts to discuss programming experts discussed

计算器c#编程 由于开发环境没有c#只好选择c-Calculator c# programming development environment, because there is no c# no other choice than c++