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Java---lessons
一本比较简单的java入门教程,为初学java的便宜提供了一个比较低的门槛(A relatively simple java introductory tutorial provides a low threshold for beginner java cheaper)
- 2012-12-30 16:49:58下载
- 积分:1
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hadoopGIS
hadoop是众所周知的云计算平台,hadoopGIS是基于hadoop进行云GIS试验的成果,实现在云环境下的数据存储、读取等功能(hadoop is well known cloud computing platform, hadoopGIS for cloud hadoop GIS based on test results, achieved under the cloud of data storage, reading and other functions)
- 2010-08-22 17:45:42下载
- 积分:1
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springboot-kafka
kakfa+springboot+flume日志管理工具,可以方便日志管理(kafka and springboot and flume log4j manage log,if you need ,you could download,thank you !)
- 2020-06-25 02:40:02下载
- 积分:1
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ddl
正则表达式的一个小例子,利用正则表达式判断文件中的字符是什么类型的。(Regular expression in a small example of the use of regular expressions in the document to determine what type of character.)
- 2008-06-08 13:36:02下载
- 积分:1
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jd-gui-1.6.2
JD-GUI是一个用于Java编程语言源代码“.class”文件反编译软件。您可以使用JD-GUI浏览和重建源代码的即时访问方法和字段,以代码高度方式来显示反编译过来的代码。(JD-GUI is a decompiling software for Java programming language source code ". class" file. You can use JD-GUI to browse and rebuild instant access methods and fields of source code to display decompiled code in code height.)
- 2020-06-22 02:00:01下载
- 积分:1
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swingmap
将指定经纬度的点在地图上显示出来,提供地图图片放大缩小和拖动功能。(The designated latitude and longitude points will be displayed on the map, providing map image zooming and zooming and dragging functions.)
- 2020-06-16 06:20:01下载
- 积分:1
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elasticsearch-5.5.2
强大的搜索引擎,目前最流行的全文搜索引擎,分享给大家一起学习,共同进步。(The powerful search engine, the most popular full text search engine, is sharing for everyone to learn together and make progress together.)
- 2018-03-24 13:34:56下载
- 积分:1
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BUS
公交查询系统 Android studio(Bus search system can used by Android studio)
- 2019-01-11 17:08:28下载
- 积分:1
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CloudSim__DE
说明: 云计算资源调度--遗传算法,利用遗传算法在cloudsim平台进行模拟任务调度,内含有差分隐私算法,以及其优化(task schedualing Cloud computing resource scheduling - genetic algorithm (ga) is used to simulate task scheduling on cloudsim platform)
- 2021-03-19 16:19:19下载
- 积分:1
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11
说明: 一只青蛙一次可以跳上1级台阶,也可以跳上2级。求该青蛙跳上一个n级的台阶总共有多少种跳法。要求:分别用普通方法和递归方法实现(A frog can jump up a step or two at a time. Find out how many jumping methods the frog can use to jump up an n-step. Requirements: Implemented by common method and recursive method respectively)
- 2019-03-10 16:48:12下载
- 积分:1