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梯形求积分
说明: C语言梯形积分,通过公式计算积分,可以用来代替matkab的函数(Trapezoid integral in C language)
- 2021-03-31 11:39:09下载
- 积分:1
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llk
实现连连看游戏的算法。采用递归的算法找实现,很参考价值。(Achieve Lianliankan game algorithms. Find a recursive algorithm implementation, it is reference value.)
- 2013-08-06 12:40:25下载
- 积分:1
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gh0st
修改过的GH0ST界面和功能调整,增加启动FLASH(Revised GH0ST interface and functionality adjustments to increase the boot FLASH)
- 2010-02-20 22:53:05下载
- 积分:1
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三线交错双向DCDCmatlab仿真
三相交错双向dcdc微电网的matlab仿真资料,仅供参考。(Matlab simulation data of three-phase staggered bidirectional DCDC microgrid are for reference only.)
- 2019-06-23 21:39:14下载
- 积分:1
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增量谐波平衡法程序
说明: 运用增量谐波平衡法求解二自由度非线性微分方程(Solving nonlinear differential equation with two degrees of freedom by incremental harmonic balance method)
- 2021-03-23 19:19:16下载
- 积分:1
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机械手手动控制及自动分拣金属材料装置。
PLC控制步进电机驱动。...
机械手手动控制及自动分拣金属材料装置。
PLC控制步进电机驱动。-Manipulator manual control and automatic sorting of metal materials, devices. PLC controlled stepper motor drive.
- 2023-03-08 06:30:04下载
- 积分:1
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Solution PowerWord conflict with Kaspersky, so long as the replacement of the Po...
解决金山词霸与卡巴斯基冲突的,只要替换了词霸下面的XdictGrb.dll就可以了-Solution PowerWord conflict with Kaspersky, so long as the replacement of the PowerWord XdictGrb.dll the following can be a
- 2022-08-07 01:02:37下载
- 积分:1
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超声换能器 超声无损检测
说明: 美国无损检测手册 超声卷(上册) 美国无损检测手册 超声卷(下册) 超声手册之超声换能器 无损检测II级培训教材 超声波检测(American nondestructive testing manual ultrasonic volume (Volume 1) American nondestructive testing manual ultrasonic volume (Volume 2) ultrasonic manual ultrasonic testing for ultrasonic transducers level II training material ultrasonic testing)
- 2019-10-22 20:07:52下载
- 积分:1
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一个早期的JSP论坛系统:EasyJForum v2.2 Discuz风格
一个早期的JSP论坛系统:EasyJForum v2.2 Discuz风格,功能方面和Discuz一样出色,JSP论坛程序不多哦,本款或许可为您提供第一手的参考范例。注:从2.1版本起,不再公开大多数源代码。
- 2022-08-25 20:30:38下载
- 积分:1
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数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的...
数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的根。
输入:
输入有多个案例。每一个案例为一行,每行只有一个整数N。当输入的N是-1时,输入结束。
输出:
每一个案例输出一行。每行只有一个数字,就是N对应的数根。
Sample input
39
-1
Sample output
3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3
- 2023-09-05 21:25:03下载
- 积分:1