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Untitled2
用matlab实现的基于最大值对图像图形处理可实现多个图像(Based on the maximum value of image and graphics processing multiple images using matlab)
- 2012-05-27 18:07:15下载
- 积分:1
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SpaceLib_MatLab_manual
Space lib tips which is so useful in matlab programing particularlly in Control engineering.
- 2011-10-13 18:10:57下载
- 积分:1
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666616psk
RLS算法,用matlab实现,用自适应算法来实现均衡,程序正确(RLS algorithm, using matlab to achieve, with an adaptive algorithm to achieve a balanced and correct procedures)
- 2012-09-05 21:51:26下载
- 积分:1
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flpropui
flpropui - Reservoir fluid properties from Batzle-Wang relations with interactive input/output dialog boxes.
- 2011-05-15 01:08:06下载
- 积分:1
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octree-based-codes
该程序介绍了有关八叉树编码的基本编程知识,对于初级学者易懂易学。(This program introduces the octree encoding basic programming knowledge, which ishelpful for junior scholars to understand.)
- 2014-10-21 19:19:45下载
- 积分:1
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ADMtoDMGimP
求双矩阵博弈的Nash平衡点,可以避免产生死循环。(Demand pairs of the Nash equilibrium point bimatrix game, can minimize the infinite loop.)
- 2009-10-25 14:29:20下载
- 积分:1
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aliiiii
providing YBus for load flow
- 2011-08-09 02:04:29下载
- 积分:1
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nijuzhen
逆矩阵 行列式的值
matlab
数值计算方法 源程序(Determinant of the value of the inverse matrix numerical method matlab source)
- 2008-07-02 13:08:48下载
- 积分:1
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gaborfilter
gabor filter implementation in matlab
- 2011-01-10 02:41:45下载
- 积分:1
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we
说明: 七单元天线阵DOA估计
clear clc
d=1 天线阵元的间距
lma=2 信号中心波长
q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向
A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子
A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)]
A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)]
A4=[exp(-2*pi*j*d*[0:6]*cos(q4)/lma)]
A=[A1,A2,A3,A4] 得出A矩阵
n=1:1900
v1=.015 四信号的频率
v2=.05
v3=.02
v4=.035
d=[1.3*cos(v1*n) 1*sin(v2(we)
- 2010-05-06 15:26:50下载
- 积分:1