基于EM算法的混合COPULA mixed-Copula

Windows密码抓取神器 代码完整 可编译通过 学习用的好代码(Windows password fetching artifact code complete Good code can be compiled by learning )

四旋翼飞控系统，包含定点，定高，自动按航迹点飞行，自动起飞，降落功能(Four-rotor flight control system)

消除文法的左递归，包括直接左递归和间接左递归(digui)

上海期货市场自动交易接口CTP开发示例代码。(CTP interface examples codes.)

Monte Carlo Simulation On Estimating the probability of a flush

说明：  关于VC++与Matlab混合编程的一些参考文献，很有参考价值(On VC++ and Matlab programming mix some reference, a good reference)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

matlab与vc联合编程 实现图形的动态显示(matlab and graphics vc joint programming to achieve the dynamic display)

波前曲扭和幅度变化对阵列测向中相干源分辨的影响(Twisted and curved wavefront amplitude variation to distinguish the impact of coherent source direction finding in an array)

利用ＶＣ＋＋与ＭＡＴＬＡＢ编程 希望多交流 也希望资源共享(VC++ and MATLAB programming hope that more exchanges also hope that the sharing of resources)