Project1

IEEE 14 bus 的连续潮流计算的MATLAB程序, 不错的参考代码。(Continuation power flow for IEEE 14 bus system)

用于ukf计算的c#代码 来源于几天几夜的辛勤劳动(none ha ha ha ha ha ha hah)

网络测试工具,一个发送,一个接收.UDP包,广播或者组播可选-network test tools, a sending, receiving one. UDP packet, broadcast or multicast optional

可用于matlab等绘制中国地图，即开即用，十分方便(It can be used in Matlab to paint a beautiful China Map.)

说明：  acis常用函数使用说明，对初学者非常有用(acis common function description is very useful for beginners)

zoj094 Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. (Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. )

GENERASTION COST MINIMIZATION (OPF)

算法设计的一个作业，输入一个正整数，把它的2~36进制形式打印出来(Algorithm design of a job, enter a positive integer, it s 2 to 36 hexadecimal form printed )

这是脱壳程序 Obsidium Explorer 的源代码 可以完成这些工作: ANALYSIS OF LOADER CODE DECRYPTION OF OVERLAY DECRYPTION OF SECTIONS DECRYPTION OF IMPORTS PORTED TO ASM (procedures Obsidium Explorer source code can complete these tasks : ANALYSIS OF LOADER CODE OF Overlay D DECRYPTION ECRYPTION OF SECTIONS OF IMPORTS PO DECRYPTION RTED TO ASM )

说明：  基于STM32与FDC2214手势识别处理程序(Hand gesture recognition processing program based on STM32 and FDC2214)