model_shuangtiaozhibo

通过正弦函数实现的光通信应用的占空比为50％或33％的RZ－DPSK信号(Sine function through the implementation of optical communication applications, the duty cycle of 50 or 33 RZ-DPSK signal)

用MATLAB编写的一个猜数字游戏 就是随机生成4位数，你要在有限的步数内猜出。 用法：输入4位数字后按’ok’键，可看到当前结果。 按answer键查看正确答案 按reset键重新开始 还有很多不成熟的地方，发上来想和大家一起商量商量 主要问题： 1、步数限制功能没有完成 2、应当在显示区保留显示以前的所有步骤，但目前只能显示当前步骤 3、按键次数没有保留，无法判断你已经猜了几次 一个小bug：若输入3位数，则会自动把第一位置0 (MATLAB prepared with a game猜数字is randomly generated 4-digit, you have to step in with a limited guess. Usage: Enter the 4 digits after ' ok' button, the current results can be seen. By the answer key to view the correct answer by the reset button to restart where there are many immature, made up and we would like to discuss the main issues discussed with: 1, step 2 did not complete the functional limitations, it should be retained in the display shows all the steps before , but currently only shows the current step 3, the number keys will not be retained to determine a number of you have guessed a small bug: if the input 3-digit, it will automatically position the first 0)

一种新的图像清晰度评价函数,该函数对经典采用八方向模板Sobel边缘检测算子来检测梯度值(a clarity-evalua tion function was researched. An improved eight model Sobel function was proposed,)

Matlab实现史密斯圆图的绘制程序。 这个Matlab程序，绘制史密斯圆图，同时绘制反射系数。(Matlab Smith chart drawing program. The Matlab program to draw a Smith chart, draw the reflection coefficient.)

控制系统计算机辅助设计——Matlab语言与应用 第三章源码(Control system for computer-aided design source)

Mobile Robot Simulation by Matlab

说明：  含风力发电机的电网系统，实时调度，频率控制，可变负荷(Real time Dispatch and Frequency control by WGRs for variable load and wind speed conditions)

matlab 实现基于dbdcan的聚类算法，帮你在matlab中简易的实现了解( it helps you study cluster alogroim in the matlab )

这个也是关于空间谱的matlab 挺好的 可以(This is on the spatial spectrum of matlab can be quite good)

Estimated number of Pi ( Method 1) how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each. Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as