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SpaceFrameElement
有限元SpaceFrameElement的matlab程序(FEA matlab SpaceFrameElement)
- 2013-10-12 23:25:41下载
- 积分:1
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rx_viterbi_decode
移动通信系统中常用的维特比解码器的实现程序。(The codes of Viterbi Decoder for mobile communication.)
- 2014-02-23 19:58:41下载
- 积分:1
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ExtractedAndRecognized
利用Hu矩对26个英文字母进行提取和识别(Using Hu moments of the 26 English letters are extracted and recognized)
- 2010-08-11 12:23:15下载
- 积分:1
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PMSM
Matlab simulation of PMSM with SPWM modulation. This is an example that use every single element of simulink library, so it can help you understand details of PMSM simulation.
This simulation module was built by my own, any questions, pleases contact me.
- 2014-12-16 16:55:44下载
- 积分:1
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FluidPipelineSimulinkModels
These Simulink blocks contain transfer functions that model the pressure and flow transients for axisymmetric 2D viscous flow of a compressible fluid in a straight rigid circular cross section pipelines. Three models are available:
(1) pressures at the ends
(2) flow rates at the ends
(3) pressure at one end and flow rate at the other
Filtering is incorporated to reduce numerical oscillation (Gibbs phenomenon). See J. Dyn. Systems, Meas. & Control vol 122 (2000) pp. 153-162.
- 2007-11-27 00:31:46下载
- 积分:1
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matlapp
MATLAB的梯度法,内点法,外点法,罚函数,惩罚函数,线性梯度法,源程序,按照提示输入,可直接运行(MATLAB' s gradient method, interior point method, outside the point of law, penalty function, penalty function, the linear gradient method, source code, follow the prompts to input, can be directly run)
- 2009-04-12 21:12:24下载
- 积分:1
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beam-forming-
是波束形成的系统图,是整个波束形成的系统,方便大家做波束形成的图。(Is a system diagram of the beam-forming, and the whole beam forming system, facilitate beamforming FIG.)
- 2012-11-13 18:08:11下载
- 积分:1
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An-Unequal-Clustering-Algorithm-
一种基于ARMA的WSN非均衡分簇路由算法(An Unequal Clustering Algorithm in Wireless Sensor Networks Based on ARMA)
- 2012-08-15 16:10:08下载
- 积分:1
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pi_method1
Estimated number of Pi ( Method 1)
how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each.
Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as
- 2013-04-29 02:49:47下载
- 积分:1
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chaptr-2-wireless-channel
WIRELESS COMMUNICATION CHAPTER 2
- 2014-01-24 14:18:49下载
- 积分:1