AMBTC

利用matlab编程实现LPC谱与语音频谱的比较。( LPC spectrum using matlab programming comparison with the speech spectrum)

利用matlab画出一朵玫瑰，建立一个基本的m文件(use matlab to paint a rose)

MATLAB命令大全，中文释义。 工程、科学研究中强有力的数学工具。(MATLAB command Guinness, Chinese Interpretation. Engineering, scientific research in a powerful mathematical tool.)

Hjorth calculation of signal

Addendum Unicycle的动力学仿真模拟, 运动控制, 美国密歇根大学研究生课程<线性与非线性控制系统>官方范例(Addendum Unicycle dynamics simulation, the motion control, the University of Michigan graduate courses < linear and nonlinear control systems> Official Examples)

可以得到很精确的幅值、频率、相位估计，是学习PCA特征提取的很好的学习资料，合成孔径雷达（SAR)目标成像仿真，有均匀线阵的CRB曲线，匹配追踪和正交匹配追踪，对信号进行频谱分析及滤波，模式识别中的bayes判别分析算法。 ( You can get a very accurate amplitude, frequency, phase estimation, Is a good learning materials to learn PCA feature extraction, Synthetic Aperture Radar (SAR) imaging simulation target, There ULA CRB curve, Matching Pursuit and orthogonal matching pursuit, The signal spectral analysis and filtering, Pattern Recognition bayes discriminant analysis algorithm. )

动态方式观察物体坠落的过程，从而达到动态的仿真效果。(The dynamic way observation object crashes process, thus achieves the dynamic simulation effect. )

光伏阵列Simulink仿真文件 光伏阵列(PV array Simulink simulation files)

to make a simulation of motors

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)