登录
首页 » Visual C++ » sqlcipher_vs2008

sqlcipher_vs2008

于 2020-06-26 发布 文件大小:4916KB
0 280
下载积分: 1 下载次数: 46

代码说明:

  支持加密Sqllite库,vs2008 + sqlite3 + sqlcipher,测试可用(Supports encryption Sqllite library, VS2008+ SQLite3+ sqlcipher, testing available)

文件列表:

demo
....\demo.cpp,2020,2015-06-01
....\demo.vcproj,4304,2015-05-31
....\demo.vcproj.SCAR-PC.建兴.user,1411,2015-06-01
....\ReadMe.txt,1165,2015-05-31
....\sqlite3.h,378697,2015-05-21
openssl
.......\aes.h,5507,2015-02-09
.......\applink.c,2892,2015-02-09
.......\asn1.h,52190,2015-02-09
.......\asn1t.h,30092,2015-02-09
.......\asn1_mac.h,19143,2015-02-09
.......\bio.h,32987,2015-02-09
.......\blowfish.h,5143,2015-02-09
.......\bn.h,36559,2015-02-09
.......\buffer.h,4652,2015-02-09
.......\camellia.h,4956,2015-02-09
.......\cast.h,4492,2015-02-09
.......\cmac.h,3244,2015-02-09
.......\cms.h,19927,2015-02-09
.......\comp.h,1978,2015-02-09
.......\conf.h,9848,2015-02-09
.......\conf_api.h,4080,2015-02-09
.......\crypto.h,24337,2015-02-09
.......\des.h,10849,2015-02-09
.......\des_old.h,18238,2015-02-09
.......\dh.h,9979,2015-02-09
.......\dsa.h,12057,2015-02-09
.......\dso.h,18095,2015-02-09
.......\dtls1.h,8066,2015-02-09
.......\ebcdic.h,610,2015-02-09
.......\ec.h,46417,2015-02-09
.......\ecdh.h,4682,2015-02-09
.......\ecdsa.h,10510,2015-02-09
.......\engine.h,40585,2015-02-09
.......\err.h,15862,2015-02-09
.......\evp.h,52791,2015-02-09
.......\e_os2.h,10444,2015-02-09
.......\hmac.h,4476,2015-02-09
.......\idea.h,4469,2015-02-09
.......\krb5_asn.h,7642,2015-02-09
.......\kssl.h,6290,2015-02-09
.......\lhash.h,9092,2015-02-09
.......\md4.h,4692,2015-02-09
.......\md5.h,4692,2015-02-09
.......\mdc2.h,3917,2015-02-09
.......\modes.h,5688,2015-02-09
.......\objects.h,36641,2015-02-09
.......\obj_mac.h,136214,2015-02-09
.......\ocsp.h,24041,2015-02-09
.......\opensslconf.h,6910,2015-02-09
.......\opensslv.h,3822,2015-02-09
.......\ossl_typ.h,7467,2015-02-09
.......\pem.h,21992,2015-02-09
.......\pem2.h,2863,2015-02-09
.......\pkcs12.h,12654,2015-02-09
.......\pkcs7.h,17944,2015-02-09
.......\pqueue.h,3649,2015-02-09
.......\rand.h,5578,2015-02-09
.......\rc2.h,4405,2015-02-09
.......\rc4.h,3797,2015-02-09
.......\ripemd.h,4327,2015-02-09
.......\rsa.h,22911,2015-02-09
.......\safestack.h,184225,2015-02-09
.......\seed.h,5714,2015-02-09
.......\sha.h,7636,2015-02-09
.......\srp.h,5378,2015-02-09
.......\srtp.h,6677,2015-02-09
.......\ssl.h,104510,2015-02-09
.......\ssl2.h,10755,2015-02-09
.......\ssl23.h,3744,2015-02-09
.......\ssl3.h,27267,2015-02-09
.......\stack.h,4412,2015-02-09
.......\symhacks.h,24302,2015-02-09
.......\tls1.h,35390,2015-02-09
.......\ts.h,31006,2015-02-09
.......\txt_db.h,4481,2015-02-09
.......\ui.h,16656,2015-02-09
.......\ui_compat.h,3439,2015-02-09
.......\whrlpool.h,1019,2015-02-09
.......\x509.h,45041,2015-02-09
.......\x509v3.h,32713,2015-02-09
.......\x509_vfy.h,22408,2015-02-09
Release
.......\demo.exe,7680,2015-06-01
.......\libeay32.dll,1174528,2015-05-27
.......\msvcr90.dll,653968,2013-08-03
.......\sqlite3.dll,635904,2015-06-01
.......\sqlite3.lib,50180,2015-06-01
sqlcipher
.........\alter.c,28572,2015-05-31
.........\analyze.c,67429,2015-05-31
.........\attach.c,17787,2015-05-31
.........\auth.c,8710,2015-05-31
.........\backup.c,28605,2015-05-31
.........\bitvec.c,13536,2015-05-31
.........\btmutex.c,9301,2015-05-31
.........\btree.c,328691,2015-05-31
.........\btree.h,9666,2015-05-31
.........\btreeInt.h,31584,2015-05-31

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • rsashuziqianming
    RSA数字签名的源代码 vc++6.0实现的版本(RSA Digital Signature vc source code version 6.0)
    2007-05-16 16:42:45下载
    积分:1
  • GPU-AES
    使用cuda的aes加解密kernel函数(the kernel function of aes encrypt)
    2012-04-27 10:15:24下载
    积分:1
  • md5
    MD5是一种被广泛使用的“消息-摘要算法”。实际上就是一个单项散列函数。(MD5 is a widely used " message- digest algorithm." Is actually a single hash function.)
    2010-12-27 16:26:46下载
    积分:1
  • Windows_Password_Logger
    windows登陆密码信息拦截,获取明文口令。程序对不同系统做了处理,在2000,2003,xp,vista上都可以截取, 在2000,2003,xp中,通过UNICODE_STRING.Length 的高8位取xor key,如果密码是编码过的,则通过ntdll.RtlRunDecodeUnicodeString解码, vista则通过AdvApi32.CredIsProtectedW判断密码是否编码过,解码用AdvApi32.CredUnprotectW。(The windows Password intercept, access to the plaintext password. Processing program on a different system in 2000, 2003, xp, vista can intercept, 2000,2003, xp UNICODE_STRING.Length high eight take xor key if the password is encoded by the ntdll.RtlRunDecodeUnicodeString decoding, vista, to judge by AdvApi32.CredIsProtectedW and password whether encoding, decoding AdvApi32.CredUnprotectW.)
    2012-09-27 11:09:00下载
    积分:1
  • AES
    AES-rijndael 算法的详细资料, 包括 AES加密算法中的SBox及其C语言实现.pdf FIPS197(chs).pdf FIPS197.pdf nist.url Rijndael.pdf rijndael算法流程.swf Rijndael算法深入的研究.doc Rijndael算法优化技术研究.doc 公钥密码体制与有限域(2).pdf 一种基于伽罗瓦域的密码系统.pdf(AES-rijndael algorithm detailed information, including the AES encryption algorithm in C language and its SBox realize. PdfFIPS197 (chs). PdfFIPS197.pdfnist.urlRijndael.pdfrijndael flow algorithm. SwfRijndael-depth study of algorithms. DocRijndael algorithm optimization technology research. Doc public key cryptosystem over finite fields and (2). pdf Galois field based on the password system. pdf)
    2008-05-06 17:17:00下载
    积分:1
  • FlexNet-Publisher-Licensing-Toolkit_Install_V11
    FlexNet Publisher Licensing Toolkit 11.9.1 Installation Guide
    2012-01-07 18:49:56下载
    积分:1
  • NDIS
    实现透明加密,驱动模型,文件过滤系统介绍(To achieve transparent encryption, drive model, document filtering system introduced)
    2011-05-19 11:26:20下载
    积分:1
  • CMAC
    在实现AES基础上,用C编写CMAC算法并调试通过。输入数据进行CMAC验证。(In the realization of AES based on the CMAC algorithm written in C and debugging. CMAC input data validation)
    2014-01-10 16:12:49下载
    积分:1
  • REVERSING
    逆向工程揭秘,包含大量加密解密详细说明。学习逆向工程必备(The secret of Reverse engineering The detailed description contains a large number of encryption and decryption. To learn reverse engineering necessary)
    2012-05-02 11:47:41下载
    积分:1
  • ASFDSAF
    题目:某个公司采用公用电话传递数据,数据是四位的整数,在传递过程中是加密的,加密规则如下:     每位数字都加上5,然后用和除以10的余数代替该数字,再将第一位和第四位交换,第二位和第三位交换。 1.程序分析: 2.程序源代码:(Topic: a company USES the public telephone relay data, data is four integers, in the relay in the process is encrypted, encryption rules are as follows: Each Numbers add 5, then use and divided by the number of 10 instead of a remnant, then the first and fourth exchange, the second and third exchange. 1. The program analysis: 2. The source code:)
    2012-05-26 20:07:28下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载