-
ning2
这是我做的第一个程序,希望大家支持下,谢谢,thank you(this is mine doing)
- 2011-12-22 12:31:27下载
- 积分:1
-
Mwheeelanalyya
Matlab中实现轮对分析的程序源码和相关的程序源码包,,能实现火车轮轨接触关系的分析
(Round of analysis of program source code and related procedures source package in Matlab, train wheel-rail contact analysis of the relationship)
- 2012-08-07 01:53:32下载
- 积分:1
-
mPPuuma560a
matlab环境下,对puma560机器人人的工作空间运动轨迹做了轨迹规划,的到轨迹云图
(Matlab environment, puma560 robot trajectories trajectory planning, to track cloud map)
- 2012-08-07 20:18:02下载
- 积分:1
-
Updated---Project-EPVB
Employee Management System
- 2015-04-04 19:27:18下载
- 积分:1
-
20130422
matlab毕业设计的一个小程序 我非常需要用用你们网站上的资料但是不知道怎么弄 我就在试试的,(Matlab graduate design a small program I really need to use on your site, but do not know how to get me to try,)
- 2013-04-24 13:43:54下载
- 积分:1
-
VideoSummary
This program is play and summary an video.
Also, this support various codecs.
- 2014-09-22 09:50:28下载
- 积分:1
-
Digital-filtering-experiment
由设计要求可知,wp<=0.2π,允许误差幅度小于1dB,ws>=0.3π内衰减应大于15dB。为了验证数字滤波器的实际滤波功能,设计程序时,把输入序列定为验证函数x(t)=4sin(100πt)以及x(t)=4sin(200πt)和x(t)=4sin(400πt)。又因为Ts=1.25ms,T=80ms,故采样点为64,即N=64,所以当M=6,可以同时调试并验证程序的滤波功能。(Seen by the design requirements, wp < = 0.2π, allow a margin of error of less than 1dB, ws> = 0.3π within attenuation greater than 15dB. In order to verify the actual filtering function of the digital filter design program, the input sequence as validation function x (t) = 4sin (100πt) and x (t) = 4sin (200πt) and x (t) = 4sin (400πt) . And because Ts = 1.25ms, T = 80ms, so the sampling points is 64, that is N = 64, so when M = 6, can debug and validate filtering program.)
- 2014-12-24 09:34:43下载
- 积分:1
-
Partial-Differential-equation
偏微分方程_编程 Routines in C, C++,
Fortran, Java® , Maple® , and MATLAB(Ordinary and Partial Differential
Equation Routines in C, C++,
Fortran, Java® , Maple® , and MATLAB)
- 2014-11-07 09:14:16下载
- 积分:1
-
viterbi-matlab
卷积编码器g1=111,g2=101
x为输入的待译码序列
x=[1,0,1,0,0,1,0,0,0,1,0,1,1,1]
x=[1,1,0,1,0,1,1,0,0,1]
x=[1,1,1,0,0,0,1,0,1,1]
a=size(x) 输入序列的长度
s=a(2)/2 译码后的m序列长度为x的一半
m=zeros(1,s) 最终结果存放
ma=zeros(1,s+1) 存放Fa路径的
mb=zeros(1,s+1) 存放Fb路径的
mc=zeros(1,s+1) 存放Fc路径的
md=zeros(1,s+1) 存放Fd路径的(viterbi decoder)
- 2015-04-20 17:06:18下载
- 积分:1
-
TrafficSimulation
说明: 关与windows程序的交通仿真。怎样描述汽车的行驶。(customs procedures and the traffic simulation. How to describe the car's ride.)
- 2006-05-06 22:02:07下载
- 积分:1