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mode
全向阵元和有向阵元的模式空间图,有助力于理解宽带波束形成(the mode pattern of ominidirectional array elements and directional array, it is helpful to understand the broadband beamforming)
- 2010-10-14 22:41:00下载
- 积分:1
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xiandaikongzhililun.pdf
学习现代控制理论的经典教材 结合matlab 之前 一定要好好看看(Study of modern control theory of the classic textbook binding matlab before must be good to have a look)
- 2012-04-24 17:40:06下载
- 积分:1
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kaerman
kaerman跟踪算法。基于“当前”统计模型的模糊自适应跟踪算法 我存的一篇论文,拿来与大家共享(kaerman program of trail or target)
- 2014-09-20 18:55:54下载
- 积分:1
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IIR
利用MATLAB提取相关系数,按照matlab的滤波思路进行编写的IIR滤波程序,已经证明好用!(MATLAB is utilized to extract the correlation coefficient, according to the writing of IIR filter MATLAB filtering ideas for program, it has been proved useful!)
- 2014-01-04 14:50:14下载
- 积分:1
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NSC
NSC program calculates BER of NSC
- 2014-01-23 22:06:16下载
- 积分:1
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gaussian_filter_constr
calculation of gaussian filter
- 2014-10-07 14:32:23下载
- 积分:1
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GDOP_target_direction
双基地声纳定位精度GDOP与目标方位的关系,目标方位为与过基线中点法线的夹角。(Bistatic sonar positioning accuracy GDOP relationship with the target position, the target azimuth angle between the baseline and over the midpoint of normals.)
- 2020-11-01 19:49:55下载
- 积分:1
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802.11a-MIMO
WLan-IEEE802.11a modified with MIMO (Multiple transmitter and receiver)
- 2014-01-17 14:09:24下载
- 积分:1
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Simulink
基于Simulink的数字滤波器的仿真
用于设计滤波的方法
(Simulink-based simulation of the digital filter used in the design of filtering methods)
- 2008-12-28 21:25:07下载
- 积分:1
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para
说明: 抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.
(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2005-12-03 18:11:10下载
- 积分:1