snr-of-differ-Quantization-in-ml

wind turbine r11 model

比例谐振控制器功能性验证 PR 控制器，对三次及技术次谐波对应控制其输出做出分析(PR controler function test)

Direct transmission energy protocol for Wireless sensor networks for heterogeneous setup.

基于pca算法的人脸识别软件，有界面，有注释，有图像库(Pca-based face recognition algorithm software, interface, with annotations, a image library)

说明：  基于常规波束形成和MVDR波束形成的非相干双声源的波达方向估计(The arithmetic solved the estimate of two signal s direction of arrival,based on the convention beam-former and MVDR beam-former.)

钟型隶属函数-e参数变化钟型隶属函数-e参数变化(Bell-shaped membership function-e parameter bell-shaped membership function-e parameters)

电磁波Yee Cell FDTD交错网格场量位置示意图 画图程序 TE 波TM波 TEM波都有(Yee Cell FDTD electromagnetic field quantity staggered grid position diagram drawing program TE, TM waves are TEM wave)

matlab有限元分析1D杆结构，2D热扩散问题，2D弹性问题，2D梁受力问题(matlab finite element analysis of 1D bar structure, 2D thermal diffusion problem, 2D elasticity problems, 2D Beams problem)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

仿真了OFDM中的SLM方法 ，并附有仿真图形，对于初学PAPR的朋友可有用(Simulation of the OFDM in the SLM method, together with simulation graphics, for a friend can be useful for beginners PAPR)