GSM

matlab中求逆矩阵函数inv的c语言实现(Compute matrix inverse.)

S u r f e r自动控制技术在气象资料 自动成图中的应用 (Ab s t r a c t ： The ma i n f un c t i o n s o f Su r fe r s o f t wa r e，Ac t i v e X a u t o ma t i o n t e c h ni q ue a nd t he i n t e r fa c e o f VB a p p l i c a t i o n a n d S u r fe r a r e i nt r o— d u c e d i n t h i s p a p e r ．I t i s a l s o i n t r o d u c e d h o w t o c o mb i n e t h e s t r o n g a b i l i t y o f d e v e l o p me n t u s i n g VB s o f t wa re a n d t he s t r o n g ma p p i n g i n Su r f e r b a s e d o n t he i n t e r fa c e．a nd t he k e y pr og r a m t o C a ／ T y o u t t h e i nt e r fa c e t e c hn i q u e a nd a c a s e o f a p pl i c a t i o n a ut o ma t i c ma p pi n g a r e pr e s e n t e d． )

task graph generator: task graph for free version 3.5

可以对数量少、残缺、不完整的数据进行预测，如人口、缺水量等。也可以对灾害发生时间进行预测。(Can be a small number, mutilated, incomplete data to predict, such as population, water shortage and so on. You can also predict the time of occurrence of the disaster.)

本书简绍了matlab编写有限元程序的整个流程(The goal of this document is to give a very brief overview and direction in the writing of nite element code using Matlab. It is assumed that the reader has a basic familiarity with the theory of the nite element method, and our attention will be mostly on the implementation. An example nite element code for analyzing static linear elastic problems written in Matlab is presented to illustrate how to program the nite element method.)

说明：  matlab教程，希望大家一起来学习，我看多好几遍了，非常不错。(matlab tutorial I hope everyone will work together to learn, I can see how good a few times, and very good.)

该代码基于灰色GM(1,1)算法，使用时，需要在函数中将自变量取为时间序列，可预测任意时间的数值(The code is based on gray GM (1,1) algorithm, when used in the function argument will be taken as time series, can predict the value of any time)

Visual c++Matlab图像处理与实用案例精选:对比度拉伸(Visual c Matlab Image Processing and practical case Featured : contrast tensile)

依据JPEG压缩标准的算法，对lena图像进行压缩，并恢复出原始图像，然后对照原始图像，对恢复出的图像进行客观评价：计算峰值信噪比PSNR及均方误差MSE。(language matlab jpeg picture compress)

这个程序针对的问题是: 17个人为成圈,依次编号为0-16,从第一号开始报数,报到3的倍数的人离开, 一直数下去,直到最后只剩1人,求此人的编号. 程序有点复杂，不过还只能算是初级的水平 (This procedure for the question is: 17 individuals into the circle, followed by numbered 0-16, from the first to begin reported the number of people who report a multiple of three to leave, to keep counting votes until the last only a person seeking this person number. program a bit complicated, but can only be considered the primary level of)