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NTL应用——大数系数多项式乘法的计算。从文件读如参数，计算多项式相乘后某项的系数(NTL application- the multiplication of big numbers coefficient polynomial )

c++ data struct stack

说明：  标准答案习题1 1.1 简述C++语言程序的结构特点。 答： （1）C++程序由一个或多个函数组成，其中至少有一个主函数main()，程序从主函数开始执行，由主函数来调用其他函数。(Standard answer to Exercise 11.1 on C++ Language program structural characteristics. Answer: (1) C++ Procedures by one or more functions, of which at least one of the main function main (), the procedure started from the main function, from the main function to call the other function.)

数据结构 堆栈 实现了以下功能： cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)

用C语言实现的普通快速排序，和随机快速排序进行对比(With ordinary C language implementation of quick sort, quick sort and compare the random)

利用双向链表实现对两大整数的相加运算。 可以修改数组长度实现更大整数的相加(Realize the use of two-way linked list of integers the sum of the two operations. Can modify the array length to achieve a greater sum of integers)

拓扑排序 -打印输出计算机本科专业4年每学期的课表(Topological sort - computer printout of undergraduate curriculum of each semester for 4 years)

Dijlstra算法 对任意图，选择合适的数据结构表示图，在此基础上实现求解最短路径的Dijkstra算法(Dijlstra algorithm to arbitrary map, select the appropriate data structures that map, on this basis to achieve solution of the Dijkstra shortest path algorithm)

数据结构与程序设计中的重点例子程序：八皇后问题(Data structure and procedures of the focus of the design example of the procedure: eight queen problem)

/*快速排序：以待排序元素中的第一个元素作为基准将带排序的元素分为三组 *大于基准元素为一组置于基准值的右边，小于基准值的元素为一组置于基准值的左边， *基准值为一组，这样就找到了基准元素的位置就确定了 *如此递归调用。直到每一组的low==high，即实现了排序的要求。 */ (/* Rapid Sort: the first element to be sorted in the element as a basis with with sorting the elements are divided into three groups* is greater than the reference element of a group is placed on the right side of the reference value, smaller than the reference value elements for a group of placed on the left side of the reference value,* reference value, a group, so that the location of the reference element is found it is determined* so recursive call. Until each group of low == high to achieve the requirements of the sort.* /)