C-CPP

这是用itpp库编写的卷积码的解码程序。由于用C++库和Intel的MKL库，所以速度飞快。同样的仿真点数， Matlab2012下用了15分半钟，而这个程序仿真只用了半分钟，相当于是matlab速度的30多倍。(This is itpp prepared for the convolutional code decoding process. Because with C++ libraries and Intel' s MKL library, so fast. The same simulation points under Matlab2012 spent 15 and a half minutes, and this program simulation with only half a minute, the equivalent of 30 times the speed of matlab.)

各种滤波器的MATLAB设计，包括低通、高通、带通(MATLAB design of the various filters, including low pass, high pass, band pass)

根据已知的三维离散数据（x,y,z）,在MATLAB中利用此函数进行三维曲面拟合，再根据polyval2d得出拟合函数的系数矩阵。(according to 3D discrete datum (x,y,z),use this function in MATLAB to fit 3D surface, and use polyval2d to get coefficient matrix)

四轴飞行器制作总结，包括四轴制作过程中马达、电调的选择，以及相关代码。(Four aircraft production summary, including the motor axis in the production process, the choice of power transfer, and the relevant code.)

gmsk的详细c语言编程过程，很适合初学者使用(the detailed c language gmsk programming process, it is suitable for beginners)

使用c语言，是随机信号分析教科书的实验程序合集，是正确的。(Using the c language, is a random signal analysis of the experimental procedure textbook collection, is correct.)

pid自适应控制器学习和程序大家学习，很好用的(请求权)

用于MATLAB中潮流计算的软件包，内含使用说明和多个测试文件，使用方便(MATLAB software is used to calculate the trend, contains instructions and multiple test files, easy to use)

用C语言 和 c++编写的卡尔曼滤波 有着详细的代码和方法 希望能帮助到你们(Written in C and C++ the kalman filter has detailed code and method can help to you hope )

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)