16-pianweifenfangcheng-shuzhijiefa

说明：  这个程序是纹理特征提取的提取，很实用的程序(This procedure is the extraction of texture feature extraction, the procedure is very useful)

免疫算法解非线性方程组matlab源程序，很好用(immune algorithm for solving systems of nonlinear equations Matlab source, easy to use)

100天线阵列1期望信号2干扰信号，用LMCV自适应波束形成(100 antenna array desired signal interference signals, adaptive beam formation LMCV)

服务桥结构静态参数识别算法Levenberg-Marquardt（L-M方法）matlab源程序(Algorithm for static parameter identification of service bridge structures Levenberg-Marquardt (L-M method) matlab source program)

蚁群PID算法代码。此方法是在MATLAB中可运行。(Ant PID algorithm code. This method can be run in MATLAB.)

VC++ and Matlab混合编程的快速实现(VC++ And Matlab Mixed Programming rapid realization of)

直接序列扩频（Direct Sequence Spread Spectrum）工作方式，简称直扩方式（DS方式）。就是用高速率的扩频序列在发射端扩展信号的频谱，而在接收端用相同的扩频码序列进行解扩，把展开的扩频信号还原成原来的信号。(irect Sequence Spread Spectrum (Direct Sequence Spread Spectrum), hereinafter referred to as Direct expansion mode (DS). Is a high rate of spread spectrum sequence extension in signal spectrum, and at the receiving end with the same spread spectrum code sequence for expansion, the expansion of the spread spectrum signal back into the original signal. )

说明：  相当全面的介绍云计算与云存储的资料，据说这是计算机科学最有发展前途的方向之一(A fairly comprehensive introduction to cloud computing and cloud storage data, which is said to computer science the most promising directions of)

说明：  跳频是按跳频序列随机改变一个信道所占有频道频率的技术。在GSM 系统中，可利用跳频技术频率分极和干扰分极的特点，改善网络质量。引入跳频技术，可保证在网络软拥塞不上升的情况下，频率复用度较小。(FH frequency hopping sequence is based on a random channel change in the country channel frequency technology. In the GSM system, can make use of frequency hopping technology sub-polar and polar characteristics of interference and improve network quality. The introduction of frequency-hopping technology to ensure that congestion in the network does not increase in the soft case, a smaller frequency reuse moment.)

说明：  某厂生产甲乙两种口味的饮料,每百箱甲饮料需用原料6千克,工人10名,可获利10万元 每百箱乙饮料需用原料5千克,工人20名,可获利9万元.今工厂共有原料60千克,工人150名,又由于其他条件所限甲饮料产量不超过8百箱.问如何安排生产计划,即两种饮料各生产多少使获利最大.进一步讨论: 1)若投资0.8万元可增加原料1千克,问应否作这项投资. 2)若每百箱甲饮料获利可增加1万元,问应否改变生产计划. (Factory production of beverages and B in two flavors, each box 100 need a drink six kilograms of raw materials, workers 10 to 100,000 yuan profit B beverage cartons per cent five kilograms of raw materials needed, workers 20, the profitability of 90,000 yuan. this plant a total of 60 kilograms of raw materials, 150 workers, and because other conditions do not yield a beverage cartons more than 8 per cent. ask what arrangements the production of projects, namely the production of two the number of drinks to make the biggest profit. further discussion : 1) if the investment 08,000 yuan to increase one kilograms of raw materials and asked whether we should make this investment. 2) If a beverage cartons per cent profit increase 10,000 yuan and asked whether or not to change the production plan.)