SharePoint-Creating-Content-Types-Programmaticall

C语言写的地铁模拟收费系统，实现了一些地铁收费的基本功能。(Metro analog toll system written in C language, some of the basic functions of the MTR charges.)

一些挺好玩的源代码 对编程会有帮助的 大家一起努力 编好程(Some very good play on the source code of all programming would be helpful for a good way to work together)

VC++ 源码编译实现的计时器小程序，比较简易的计时器，比秒要再快一些，不过这个时间频率是可以调的，如图所示，点击开始计时功能，计时器就开始工作了，可看到数字在不停的增大。(Timer applets VC++ source compiler implementation, relatively simple timer than seconds again faster, but this time frequency can be adjusted, as shown, click the start timing function the timer began working, can be see the numbers kept increasing.)

孙鑫VC++视频教学所有源代码 无需密码 直接使用(Xin Sun VC++ source code for all the video instruction)

编写程序用静态成员的方法实现对班费的管理，要求定义一个类Student，除了声明一个存放班费的静态成员，还要分别定义一个上交班费的成员函数Contribute（），花费班费的成员函数Spend（）和显示班费的静态成员函数Display（）(Write a program with static member class fee management, require the definition of a class Student, stored in addition to declare a static member of the class fee, but also define a member function of a shift fee Contribute (), a member of the spending class fee spend () function and display class fee static member function display ())

说明：  /汉诺塔递归算法过程解析: //汉诺塔（又称河内塔）问题是印度的一个古老的传说。开天辟地的神勃拉玛在一个庙里留下了三根金刚石 //的棒，第一根上面套着64个圆的金片，最大的一个在底下，其余一个比一个小，依次叠上去，庙里的众僧 //不倦地把它们一个个地从这根棒搬到另一根棒上，规定可利用中间的一根棒作为帮助，但每次只能搬一个， //而且大的不能放在小的上面。解答结果请自己运行计算，程序见尾部。面对庞大的数字(移动圆片的次数) //18446744073709551615，看来，众僧们耗尽毕生精力也不可能完成金片的移动。 //后来，这个传说就演变为汉诺塔游戏:(err)

一个可以在自己的电脑屏幕上生成烟花的小程序，可以烟花没有设计成圆的(One can generate fireworks on their computer screen applet, you can not designed to circle fireworks)

这是使用 visual basic 控制及模拟 7seg ， 从电脑输出到project board 上面( 请把inpout32.dll放进system32 里面）(This is the use of visual basic control and Analog 7seg, from the computer output to project board above (please put into inpout32.dll inside system32))

抑制载波型差分相位调制，借鉴了主成分分析算法（PCA），有CDF三角函数曲线/三维曲线图。( Suppressed carrier type differential phase modulation, It draws on principal component analysis algorithm (PCA), There CDF trigonometric curve/3D graphs.)

用于求三组数，每组数的各个位都不相同。第二组数为第一组的2倍，第3组数为第一组的3倍(Is used to find the number of three, the number of the bits in each group are different. The second number of groups for the first group of two times the number of the third group of three times the first group)