anli21.5-5

运用matlab实现数字滤波器，主要是采用的频率采样法(Realize the use of matlab digital filter is mainly used in the frequency sampling method)

刘金坤《先进 PID 控制及其 MATLAB 仿真》书上第五章源程序。供大家参考。(Liu Jinkun " Advanced PID Control and MATLAB Simulation" Chapter book source. For your reference.)

Model Predictive Control Eduardo F. Camacho and Carlos Bordons

VanderPoll oscilator simulation

这是一本matlab的入门教材，对matlab介绍很精简，电子版画面非常清楚，适合初学者学习(This is a Matlab introductory textbook description is very concise, very clear picture of the electronic version, suitable for beginners to learn matlab)

在matlab实现直线插补仿真，对观察插补原理有良好的效果。(In matlab linear interpolation simulation，To observe interpolation theory has a good effect)

generate LFM pulse waveform

NEWMARK方法求解结构动力学源程序，可求解较大自由度时的响应(newmark algorithm source)

基于matlab GUI界面设计,LYYWKyo参数数学方法是部分子空间法，采用了小波去噪的思想，BP神经网络用于函数拟合与模式识别，PnTuuBt条件包含特征值与特征向量的提取、训练样本以及最后的识别，包括主成分分析、因子分析、贝叶斯分析。( Based on matlab GUI interface design, LYYWKyo parameter Mathematics is part of the subspace, Using wavelet denoising thought, BP neural network function fitting and pattern recognition, PnTuuBt condition Contains the eigenvalue and eigenvector extraction, the training sample, and the final recognition, Including principal component analysis, factor analysis, Bayesian analysis.)

clear all I=imread( lena.bmp ) figure imshow(I) I2=imrotate(I,-4, bilinear ) 逆时针旋转4度 figure imshow(I2) I3=fliplr(I) 垂直镜像 figure imshow(I3) I4=imresize(I,0.5, bilinear ) 缩小为原图的1/2 figure imshow(I4) A=double(I) 转换为double类型 计算7个不变矩 [nc,nr]=size(A) [x,y]=meshgrid(1:nr,1:nc) 得到网格 x=x(:) y=y(:) A=A(:) m.m00=sum(A) if m.m00==0 m.m00=eps end m.m10=sum(x.*A) m.m01=sum(y.*A) 计算均值 xmean=m.m10/m.m00 ymean=m.m01/m.m00 计算中心矩(li9_23.rar cm.cm00=m.m00 cm.cm02=(sum((y-ymean).^2.*A))/(m.m00^2) cm.cm03=(sum((y-ymean).^3.*A))/(m.m00^2.5) cm.cm11=(sum((x-xmean).*(y-ymean).*A))/(m.m00^2) cm.cm12=(sum((x-xmean).*(y-ymean).^2.*A))/(m.m00^2.5) cm.cm20=(sum((x-xmean).^2.*A))/(m.m00^2) cm.cm21=(sum((x-xmean).^2.*(y-ymean).*A))/(m.m00^2.5) cm.cm30=(sum((x-xmean).^3.*A))/(m.m00^2.5) im(1)=cm.cm20+cm.cm02 im(2)=(cm.cm20-cm.cm02)^2+4*cm.cm11^2 im(3)=(cm.cm30-3*cm.cm12)^2+(3*cm.cm21-cm.cm03)^2 im(4)=(cm.cm30+cm.cm12)^2+(cm.cm21+cm.cm03)^2 im(5)=(cm.cm30-3*cm.cm12)*(cm.cm30+cm.cm12)... *((cm.cm30+cm.cm12)^2-3*(cm.cm21+cm.cm03)^2)... +(3*cm.cm21-cm.cm03)*(cm.cm21+cm.cm03)... +(3*(cm.cm30+cm.cm12)^2-(cm.cm21+cm.cm03)^2) im(6)=(cm.cm20-cm.cm02)*((cm.cm30+cm.cm12)^2-(cm.cm21+cm.cm03)^2)... +4*cm.cm11*(cm.cm30+cm.cm12)*(cm.cm21+cm.cm03) im(7)=(3*cm.cm21-cm.cm03)*(cm.cm30+cm.cm12)... *((cm.cm30+cm.cm12)^2-3*(cm.cm21+cm.cm03)^2)... +(3*cm.cm12-cm.cm30)*(cm.cm21+cm.cm03)... *()