ElGamal

实现维吉尼亚密码，用键盘接收明文和密钥，屏幕打印密文和解密后的明文。 可以实现：大小写敏感，明文小写则密文大写，明文大写则密文小写输出，注意输入的健壮性控制，明文字符超出字符集后保留原文(Virginia to achieve the password, use the keyboard to receive the plaintext and the key, the screen printing ciphertext and the decrypted plaintext. Can be achieved: case sensitive, then the ciphertext plaintext lowercase uppercase, lowercase plaintext ciphertext output is capital, pay attention to the robustness of the control input, plaintext characters out retain the original character set)

des经典加密算法，实现数据交互过程中的保密(des classical encryption algorithm, data confidentiality during the interaction)

转下的源代码程序,此程序需要密码,但可以正常使用,并可对后台进行部分修改(Transfer the source code under the program, this program requires a password, but can be used normally, it may also be part of the background changes)

壳代码，对于学习壳编写的同学具有一定的参考价值，绝对经典(Shell code, written for students to learn the shell has a certain reference value, an absolute classic)

vigenerecipher加密解密算法实例 使用vigenerecipher算法加密字符串 可输入任意密钥(vigenerecipher examples of encryption and decryption algorithms String encryption algorithm using the vigenerecipher Can enter any key)

Seed加密体制代码，韩国的分组密码加密体制。(Seed encryption system code block cipher encryption system in Korea.)

加解密！实现微软的加解密的小例子。在用微软的加解密时的一点心得(Encryption and decryption! Microsoft' s encryption and decryption to achieve a small example.)

题目：某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下： 　　　 每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。 1.程序分析： 2.程序源代码：(Topic: a company USES the public telephone relay data, data is four integers, in the relay in the process is encrypted, encryption rules are as follows: Each Numbers add 5, then use and divided by the number of 10 instead of a remnant, then the first and fourth exchange, the second and third exchange. 1. The program analysis: 2. The source code:)

身份证15位转18位的算法原码，可以自动将转换后的结果放入剪贴板中(Algorithm of the original code ID card 15 turn 18, you can automatically converted into the clipboard)

说明：  编制程序，将输入的一行字符以加密的形式输出，然后将其解密，解密的字符串序列与输入的正文相比较，吻合时输出解密的正文，否则解密失败。 加密时，将每个字符的ascii码依次反复加上“4962873”中的数字，并在32（‘’）~122（‘z’）之间作模运算。解密与加密的顺序相反。例如输入正文“the result of 3 and 2 is not 8” 结果为： (Programming, the input line character output in an encrypted form, and then decrypted, the decrypted text sequence of characters compared with the input, output to decrypt the body of the agreement, otherwise the decryption failed. Encryption, ascii code of each character in turn repeatedly with &quot 4962873&quot in the figures, and 32 (' ' )~ 122 (' z' ) as a model between the operations. Decryption and encryption in reverse order. For example, enter the text &quot the result of 3 and 2 is not 8&quot results:)