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xppaut_latest.tar
XPPOUT latest, Window GUI
- 2015-09-09 13:33:07下载
- 积分:1
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zcgzxl
最长公共子序列的 c代码,可以直接运行获得结果。(C code for the longest common subsequence can be run directly.)
- 2013-12-04 16:13:33下载
- 积分:1
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weifenfangchengdeshujijiefa
运用MATLAB求解偏微分方程的数值解的程序(Numerical Solution of Partial Differential Equations MATLAB program)
- 2011-05-29 23:31:28下载
- 积分:1
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Accelerating_Matlab_with_CUDA
Nivada之CUDA,加速Matlab运算的文档资料。(Nivada of CUDA, speed up the Matlab computing documentation.)
- 2009-12-23 10:20:18下载
- 积分:1
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zheji
地震褶积模型,最简单的抛物线,可以在修改增加内容(seismic conv models)
- 2015-01-10 11:18:15下载
- 积分:1
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Recursive_integer_division
递归法求解整数划分。
整数划分,是指把一个正整数n写成如下形式:
n=m1+m2+…+mi (其中mi为正整数,并且1 <= mi <= n),则{m1,m2,...,mi}为n的一个划分。
如果{m1,m2,...,mi}中的最大值不超过m,即max(m1,m2,...,mi)<=m,则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m) (Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m) )
- 2014-02-06 14:21:38下载
- 积分:1
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yuyin
用matlab采集语音,信号加噪去噪,以及fft变换(With Matlab acquisition Voice, the signal plus noise denoising, and fft transform)
- 2013-05-06 10:15:05下载
- 积分:1
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vcPP6.0
仿真火车站的站场图,可以办理进路,显示信号机,单操,单锁道岔等功能(Simulation Station station map, you can handle into the road.)
- 2013-11-23 17:46:30下载
- 积分:1
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exchangeline
中国一号信令线路信令中国一号信令线路信令(digital channel associater exchange line signalling public network, standard)
- 2010-01-25 14:21:20下载
- 积分:1
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clsProcess
进程操作的类,可以从进程名枚举进程PID,也可以从窗口标题查找,打开进程,读取长整型,写入长整型,读取字节数组,写入字节数组.压缩包内包含有一个破解示例,破解掉一个判断密码是否正确的程序(仅在内存中进行,不破坏原文件)(Process operations class, you can enumerate the process name from the process PID, you can search for the title from the window, open the process, read a long integer, write long integer, byte array to read, write byte array. Tarball sample contains a crack, break out a password to determine whether the correct procedure (only in memory, not a destruction of the original document))
- 2009-12-18 17:27:35下载
- 积分:1