hechaboshu

能很好的帮助学习MATLAB，我自己正学习中(Can be very helpful in learning MATLAB, is the study of my own)

说明：  用多种方式进行神经网络模拟，比较了多种模拟方法的优劣(In many ways the neural network simulation to compare the advantages and disadvantages of various simulation)

文章主要介绍了利用MATCOM进行VC和MATLAB 混合编程的步骤与优点, 并将其用于SAR 图像处理与质量评估软件开发。该软件通过图形与菜单, 界面用户只需进行简 单的菜单操作就可以得到直观的处理和评估结果, 为开展SAR 图像处理、质量评估研究提供了一个有力的工具。(Article introduces the use of MATCOM for VC++ and MATLAB programming steps and advantages of mixed and used in SAR image processing and quality assessment of software development. The software graphics and menus, just a simple user interface, menu operations can be intuitive handling and evaluation of results, for carrying out SAR image processing, quality assessment study provides a powerful tool.)

这是一个Matlab实现的PWM型直流变换器的Simulink仿真，变换方式是Buck-Boost变换方式。示例，提供了一个从5伏到25伏电压，的升压变换。(This is a Matlab Simulink simulation of PWM DC-DC converter, and transform the way Buck-Boost transform. Example, from 5 volts to 25 volts, the boost transformation.)

利用牛顿法对配电网进行潮流计算，能够准确的计算出结果(Using Newton s method for distribution network power flow calculation, the results can be accurately calculated)

关于谱分析的一些算法，其中包括周期图法、Blackman-Turkey法、Yule-Walker方程求解、最小二乘AR、最小二乘ARMA、ESPRIT、MUSIC、Root-MUSIC、Capon、和AIC准则等等经典算法。(Classical algorithm on Spectral Analysis, including periodigram, Blackman-Trukey, Yule-Walker,LSAR, LSARMA,ESPRIT, MUSIC, Root-MUSIC, Capon, AIC and so on.)

改进的OFDM 子载波分配、功率分配 注水算法(Improved OFDM subcarrier allocation, power allocation, algorithm water)

ofdm papr程序，适用于slm，pts等(ofdm papr procedures applicable to slm, pts, etc.)

这是一个音像高低通滤波MATLAB代码，其中包括巴特沃斯低通滤波，高斯高通滤波，高斯低通滤波，理想矩形低通滤波，理想圆形低通滤波……(This is a sound image high and low pass filter MATLAB code, which includes Butterworth low-pass filter, Gaussian high-pass filter, Gaussian low-pass filter, ideal rectangular low-pass filter, ideal circular low-pass filter ...)

自己些的Matlab中有关节点重新排序的程序，可以解决网络重构中的首节点与末节点不对应的问题(Own some of the Matlab program to reorder the nodes can solve the network reconfiguration in the first node and end node does not correspond to the problem)