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jifen

于 2012-12-02 发布文件大小:22KB

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下载积分: 1 下载次数: 18

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代码说明：

各种数值积分，龙贝格积分。反常积分。高斯积分。三重积分。(Various numerical integration Romberg integration. Improper integrals. Gaussian integral. Triple integral.)

文件列表：

fout
....\C3
....\..\GAULEG.TXT,682,2000-09-19
....\..\MIDEXP.TXT,519,2000-09-14
....\..\MIDINF.TXT,607,2000-09-13
....\..\MIDPNT.TXT,484,2000-09-13
....\..\MIDSQL.TXT,600,2000-09-13
....\..\MIDSQU.TXT,600,2000-09-13
....\..\QGAUS.TXT,491,2000-09-13
....\..\QROMB.TXT,452,2000-09-13
....\..\QROMO.TXT,663,2000-09-13
....\..\QSIMP.TXT,317,2000-09-13
....\..\QTRAP.TXT,254,2000-09-13
....\..\QUAD3D.TXT,380,2000-09-13
....\..\TRAPZD.TXT,399,2000-09-13
....\D3
....\..\D3R1.TXT,776,2000-09-13
....\..\D3R10.TXT,2405,2000-09-13
....\..\D3R2.TXT,677,2000-09-13
....\..\D3R3.TXT,677,2000-09-19
....\..\D3R4.TXT,677,2000-12-24
....\..\D3R5.TXT,673,2000-09-13
....\..\D3R6.TXT,2041,2000-09-13
....\..\D3R8.TXT,565,2000-09-13
....\..\D3R9.TXT,873,2000-09-19
....\V3
....\..\D3R1.FRM,1907,2000-09-13
....\..\D3R1.VBP,553,2000-09-13
....\..\D3R1.VBW,49,2000-09-13
....\..\D3R10.FRM,3514,2000-09-13
....\..\D3R10.VBP,536,2000-09-13
....\..\D3R10.VBW,49,2000-09-13
....\..\D3R2.FRM,2119,2000-09-13
....\..\D3R2.VBP,553,2000-09-13
....\..\D3R2.VBW,49,2000-09-14
....\..\D3R3.FRM,2182,2000-09-13
....\..\D3R3.VBP,553,2000-09-13
....\..\D3R3.VBW,49,2000-09-19
....\..\D3R4.FRM,3278,2000-12-24
....\..\D3R4.VBP,580,2000-12-24
....\..\D3R4.VBW,53,2000-12-24
....\..\D3R5.FRM,1889,2000-09-13
....\..\D3R5.VBP,553,2000-09-13
....\..\D3R5.VBW,53,2000-09-13
....\..\D3R6.FRM,6634,2000-09-13
....\..\D3R6.VBP,553,2000-09-13
....\..\D3R6.VBW,49,2000-09-13
....\..\D3R8.FRM,1783,2000-09-13
....\..\D3R8.VBP,553,2000-09-13
....\..\D3R8.VBW,47,2000-09-13
....\..\D3R9.FRM,2286,2000-09-19
....\..\D3R9.VBP,553,2000-09-19
....\..\D3R9.VBW,47,2000-12-26

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Cholesky
该程序是正定矩阵的Cholesky分解实例，Cholesky是矩阵分解常用的方法(The procedure is the Cholesky decomposition of positive definite matrix example, Cholesky matrix decomposition is a commonly used method)

2007-10-11 10:59:30下载

积分：1
Desktop
弗洛伊德算法最短距离的实现，输入为邻接矩阵，输出为最短距离矩阵。(Freud' s realization of the algorithm for the shortest distance, enter the adjacency matrix output for the shortest distance matrix.)

2012-09-02 15:12:56下载

积分：1
平面问题的有限元程序
说明：平面问题的有限元基础，大家可以参考一下学习学习(The finite element foundation of the plane problem, you can refer to it)

2020-06-21 21:56:58下载

积分：1
NHMT
说明：埃特金不等距插值，有例子，检验过，很顺利(Aitken non-equidistant interpolation, there are examples of tests, it is smooth)

2008-11-30 19:02:40下载

积分：1
Euler_DG_Quadrilateral_2D
自己写了一个二维Euler方程的间断有限元程序上次发了一个三角形单元的程序因为不是曲边单元所以在圆柱后面容易形成涡现在把程序改为曲边四边形单元了没有涡出现单元是8节点四边形单元节点编号顺序是 1 5 2 6 3 7 4 8 也就是四个角点依次是1 2 3 4 然后是边的中点编号 5 6 7 8. 时间推进采用 Runge-Kutta 方法数值通量采用全局Lax-Friedrichs通量仍然不能捕捉激波因为没有做重构或者加人工粘性等这个做出来了再发一次。程序没有进行优化比如说内存的消耗没有优化比如直边单元的边界积分仍然采用了曲边的积分方法增加了计算量比如面积分、线积分都是采用的是Gauss- Legendre-Lobatto积分积分精度会比一般的Gauss-Legendre积分精度低一阶等等问题。二维的纯属交流性质就没有考虑这些问题 ^_^ 如果物面全部是直边那么只要改变一个参数N 就可以获得不同的计算精度且具有谱精度因为单元的节点是Gauss-Legendre-Lobatto积分点。其实就是谱元法（物面是曲边的情况我不清楚是不是也可以通过提高基函数的阶数也就是增加N 来提高计算精度）(Wrote a two-dimensional Euler equations with discontinuous finite element program Last made a triangular element of the program, not curved edge unit is so easy to form a vortex in the cylinder behind the Program to curved edge quadrilateral element vortices appear Unit is the order of 8-node quadrilateral element node number is 15,263,748 which is the four corners of the points in turn Is 1234 and then the side of the midpoint of the number 5678. Time promote the use of Runge-Kutta method Numerical flux of the overall situation of Lax-Friedrichs, flux Still can not capture the shock wave did not do the reconstruction or artificial viscosity do it Zaifayici. The program is not optimized for example, memory consumption is not optimized such as straight-edge boundary integral of the unit is still mining Integral method to increase the amount of computation such as surface integral with a curved edge, the line integral using the Gauss- The Legendr)

2021-01-29 12:58:40下载

积分：1
INORDER_PRE_POST_TRAVERSE
PRE IN POST OREDER TRAVERSAL C++ CODE VISUAL

2016-05-11 20:58:00下载

积分：1
1
说明：一维黎曼问题，一维问题，即激波管问题，是一个典型的一维可压缩无黏气体动力学问题，并有解析解。对它采用二阶精度两步差分格式进行数值求解。(Riemann problem, One dimensional problem, the shock tube problem, is a typical one-dimensional compressible non viscous gas dynamic problem with analytic solutions. It is solved numerically by two order two step difference scheme.)

2018-04-29 14:56:36下载

积分：1
cpp
说明：你输入一个长方体的长和宽以及高，就可以输出他的面积(input height，width，length，output volume)

2010-04-11 21:19:10下载

积分：1
DK
说明：邓肯张在ansys中的二次开发，适合于土体有限元分析(second development of duncan-zhang in ansys,it s be used to ansys)

2015-01-09 09:27:07下载

积分：1
half
计算半方差，如果按克里金法计算插值要求计算半方差，用此程序可实现。(Calculation of semi-variance, if the Kriging interpolation method call for the calculation of semi-variance, using this procedure can be realized.)

2008-05-15 13:48:06下载

积分：1

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