cal

说明：  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)

在VC++6.0中利用MATCOM接口调用MATLAB中的.mat文件进行数据处理(In VC++6.0 using MATCOM interface calls the MATLAB. Mat file for data processing)

说明：  要求如下： 数组与函数 1. 实验目的：掌握数组与函数的使用方法，掌握,面向过程的程序设计方法，复习分支与循环语句的使用。... (Requirements are as follows: the array with the function 1. Experimental purposes: taking control of the array with the function to use, master, process-oriented program design method, review the use of branching and loop statements. ...)

cpio源码,cpio2-11,不要钱了，随便看看(cpio code)

清华大学OFDM原理性讲座，比较基础。对初学者也许有点用处(Tsinghua University, OFDM principle of lectures basis of comparison. May be of some use for beginners)

Some mathematical functions

通过程序控制CMD程序的输出,并对其进行解析和过滤(CMD program through the control output, and its analysis and filtering)

基于嵌入式GUI的设计源码，在windows上开发(based on vc6.0, the GUI of embeded OS)

在振动台试验后由测得的加速度值两次积分求位移(Acceleration of displacement)

4个收集的vc，matlab纹理检测，纹理分割代码和数篇IEEE纹理分割，纹理缺陷检测论文(Number of Posts IEEE texture segmentation, texture defect detection papers and four personal collection vc, matlab code texture segmentation)