call2

matlab下载用到的激活文件，实在不知道怎么藐视(matlab download activation files used, it is not to know how contempt)

book on programming in crystal report

时间片轮转法实现处理器调度的程序.^-^(time slice Web Method processor scheduling procedures .^-^)

说明：  使用MatlaB进行仿真，分析各种频谱感知方法，对比优缺点，展望未来发展情况(Use MatlaB simulation, analysis of various spectrum sensing method, compared the advantages and disadvantages, the future development of)

用实例演示如何在matlab中调用c++，适用于初学者，很好的例子(With examples demonstrate how to call c++ in matlab for beginners, a good example)

说明：  面向组织结构的访问控制模型Structure-oriented access control model(Structure-oriented access control model)

地震数字处理的基本程序，其中包括滤波褶积，fft，dft，自相关互相关，以及偏移等，对地质学人员比较有用(Digital processing seismic basic procedures, including convolution filter, fft, dft, autocorrelation cross correlation, and offset, etc., more useful for people geology)

用互相关法求相对剩余静校正量；并用时差统计法或相关函数统计法分离，最后可求出记录道的绝对剩余静校正量。(Using cross correlation method the relative residual statics and separated by the difference method or statistical correlation function statistics of the last track can be obtained an absolute residual statics.)

希望对你有帮助，包含了整个的过程，我研究了好久，收获很大。(I hope it can help you, contains the whole process, I studied for a long time and fruitful.)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)