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VB-Code
以 Visual Basic 作为开发工具,Access 作为后台数据库,这是经典的单机版数据库管理信息系统的开发组合。包括10个不同的实例供大家学习。(Visual Basic as a development tool, Access as the backend , which is the development of a combination of classic stand-alone management information system. Including 10 different instances for the study.)
- 2015-08-12 13:54:28下载
- 积分:1
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c语言支持自己创建迷宫,并求解最短路径
说明: 支持自己设计迷宫,并一键自动求解最短路径,游戏界面附有操作说明(Supports oneself to design the maze, and automatically solves the shortest path with one key. The game interface is accompanied by operation instructions.)
- 2019-06-08 18:14:59下载
- 积分:1
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regedit
说明: 实现了注册表编程的一般操作,例如查询、修改等(Achieved the general operation of the registry program, such as query, modify, etc.)
- 2008-12-08 15:11:35下载
- 积分:1
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STM32F4-Project
ARMSTM32F4xx的开发源代码。包括SD卡、USB通信、AD采集(ARMSTM32F4xx development source code)
- 2013-02-28 13:23:18下载
- 积分:1
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Pedump
把exe里面的资源通通取出来,实现反编译(Exe inside to check out all the resources, realize decompile)
- 2007-07-19 11:03:23下载
- 积分:1
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GifCodec
参考网上的资料写的gif编解码。
编码用gdi解析常用图片格式,然后组装成gif
解码吧gif的每一帧转换成dib
gif文件格式网上有很多介绍
gif用的变长lzw压缩算法:
没弄懂原理,只知道过程。压缩取一个字符作为后缀,看看字符串是否存在。存在,用对应的编码作为前缀继续取;不存在把字符串添加到字典,前缀添加到输出流,后缀作为前缀继续取。解压取一个编码看看字典中是否存在。存在用对应的字符串的第一个字符作为后缀,看看当前字符串是否存在,不存在添加到字典中,后缀作为前缀,前缀对应的字符串添加到输出流,继续取;编码不存在,前缀对应的字符串的第一个字符作为后缀(这时当前字符串肯定不存在,字典中下一个可用编码肯定等于刚取出的编码),字符串添加到字典中,编码作为前缀,前缀对应的字符串添加到输出流,继续取。
编码流转换成字节流是按位从低到高的,window是小端模式(低字节在低地址),字节内低位在右边。
24位dib转换成8位dib时使用的八叉树算法
图片拉伸时参考的网上的双线性插值算法。
字典满了位数加一,位数是12时不加(Online reference materials written gif codec.
Encoded using gdi resolve common image formats, and then assembled into a gif
Each frame decode it into a gif dib
There are many online gif file format introduced
gif lzw with variable length compression algorithm:
Did not understand the principle, only know the process. Compression takes a character as a suffix, and see if there is a string. Exist as a prefix to continue to take with the corresponding encoding there is no string to add to the dictionary, a prefix added to the output stream, the suffix as a prefix to continue to take. Take a look at extracting coding dictionary exists. Exist with the corresponding first character string as a suffix to see the current string exists, there is no add to the dictionary, the suffix as a prefix, the corresponding string to the output stream, continue to take coding does not exist, prefix corresponding first character string as a suffix (when the current string certainly does not exis)
- 2015-01-17 20:22:25下载
- 积分:1
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zoj1094
zoj094
Matrix multiplication problem is a typical example of dynamical programming.
Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose.
For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix.
There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C).
The first one takes 15000 elementary multiplications, but the second one only 3500.
Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy.
(Matrix multiplication problem is a typical example of dynamical programming.
Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose.
For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix.
There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C).
The first one takes 15000 elementary multiplications, but the second one only 3500.
Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy.
)
- 2012-06-10 10:38:53下载
- 积分:1
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xrpcv_2202
Offline eamuse server
- 2020-06-25 03:00:02下载
- 积分:1
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GraphColorPage
GraphColorPage.cpp the ClassWizard will add member initialization here(the ClassWizard will GraphColorPage.cpp add member initialization here)
- 2007-03-16 22:45:32下载
- 积分:1
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很好……你可以学到更多的东西…
两线程同时监控服务器的两个端口,从其中一个端口接收到得数据都会通过另一端口转发给另一客户端。-It s very good...you can learn much more...
- 2023-04-09 10:50:04下载
- 积分:1