1.BATChargenew(1)

Some elementary important source files

arcserver+C#实现换冲洗分析功能，刘光书本源代码实现。(arcserver+C# flush analysis capabilities to achieve change, Liu books source code.)

IRLS不等距时窗,用于多次波自适应减去过程中，更加准确的处理(this is IRLS code)

104规约程序，用于电力IEC104规约分析(104PROTOCAL)

matlab fir chebshev LPF

总体经验模态分解（EEMD）的程序，适合初学者学习。(Overall empirical mode decomposition (EEMD) procedures, suitable for beginners to learn.)

电能质量3 5 7次谐波治理 以三相不平衡负载的影响搭建的简单simulink模型(A simple Simulink model for the 357 harmonic control of power quality based on the influence of unbalanced three-phase loads)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

How C# calls Matlab? This is the solution

运用matlab语言编译，进行聚类分析，并且给出了matlab界面。(failed to translate)