yanzhengxingxi-

说明：  直接调用NTFS文件驱动检测隐藏文件 绕过hook终极武器(NTFS file driver detected a direct call to bypass the hook ultimate weapon hidden files)

一款优秀的有趣味的远程桌面控制代码，采用VC++编写，由一个客户端和一个服务端组成(A good interesting remote desktop control code, using VC++ written by a client and a server component)

用VC++2005写的禁用与启用U盘的源程序！(Written with VC++2005 U disk to disable and enable the source!)

说明：  利用动态规划法，求出字符串A变为字符串B的最小操作数。（每次只能操作一个字符）(Find the minimum operand that turns string A into string B)

说明：  调用可执行程序，C语言进行输入，得到基于GIM格网的电离层总电子含量(The total electron content of the ionosphere based on GIM grid is obtained by using executable program and C language for input)

delphi bakery db app

(1)设计一个数字低通滤波器．设计指标如下： 通带内幅度衰减人大于1dB 阻带内幅度衰减大于15dB (2)编制计算设计的数字滤波器幅度特性与相位特性程序，并进行实验验证； (3)编制实现该数字滤波器程序并且模拟实现数字滤波 ①分别让满足所设计滤波器的通带、过滤带、阻带频率特性的正弦波通过滤波器，验证滤波器性能。 ②改变正弦抽样时间，验证数字低通滤波器的模拟截止频率是抽样时间的函数。((1) Design a digital low-pass filter. Design specifications are as follows: pass-band attenuation range of people within a range greater than 1dB stopband attenuation greater than 15dB (2) the preparation of calculation and design of digital filter amplitude characteristics and phase characteristics of processes and experimental verification (3) the preparation of implementation of the digital filter program and simulate digital filtering ① were designed to meet the pass-band filter, filter belt, stop-band frequency characteristics of the sine wave through the filter, verify the filter performance. ② change the sine sampling time, verify that the number of analog low-pass filter cutoff frequency is the sampling function of time.)

此源碼可以用來做為MC13224的測試RF效能，用來驗證天線設計的好壞(the program can test Freescale-MC13224 RF performance )

说明：  实现了快速排序、随机排序以及中位排序查找第k小元素(Fast sorting, random sorting and median sorting are realized to find the k-th small element)

1-持续CSMA协议下，当一个用户要发送数据时，它首先侦听信道，看是否有其他站点在传送。如果信道忙，就持续等待直到信道空闲时，便将数据送出。若发生冲突，就等待一个随机长的时间，然后重新侦听。 对于这种协议，先考虑当前帧i时的前一帧时i-1，得到前一帧时的最后一帧frame0（相对时间最大的帧）的相对时间dt0，然后再在当前帧时查看有哪些帧的相对时间会小于dt0，这些帧若是发送就会与frame0发生冲突，所以这些帧就进入持续等待状态，这些帧并没有发送。再考虑当前帧余下的帧（dt > dt0），它们中的第一帧侦听到信道处于空闲状态，所以就发送，而其他的帧由于第一帧的发送又处于等待状态。若有大于或等于2个帧的相对时间相等，且它们又同时侦听到信道空闲时，就会同时发送而导致冲突，冲突发生后的处理方法同上两个协议的一样。 -1- CSMA continued under the agreement, when a user to send data, it first interception Channel to see if there are other sites in transmission. If Channel busy, continuing to wait until the idle channel, and put more information out. If there is conflict, it is a long wait for a random time, then re-interception. Such agreements, to consider the current frame i am one of the former when i-1, be a time before the final one frame0 (relative to the time frame) the relative dt0 time, and then when the current frame to detect what the relative time frame will be less than dt0, these frames will be sent if and frame0 conflict, th