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90139945
由于传统的 COM 技术使用静态的非托管编程,net使用动态的托管编程(Because of the traditional COM technology using static unmanaged programming,.net using dynamic managed programming)
- 2017-04-24 13:49:33下载
- 积分:1
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HasPositionalPredChecker
Has Positional Pred Checker extends X Path Visitor Source Code for Andriod.
- 2014-01-01 11:38:11下载
- 积分:1
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huiwen
回文串的实现,适合初学java的人使用和阅读(Palindrome string implementations, suitable for beginners java people use and read)
- 2014-05-01 14:56:03下载
- 积分:1
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osb-105-SimpleDatabaseQueries
osb访问数据库例子,很难找,分享出来给大家使用,请大家支持(osb access to the example, it is difficult to find, share out for everyone to use, please support)
- 2016-03-23 08:43:14下载
- 积分:1
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网络版本的中国象棋服务器源代码,实现象棋的基本功能,对大家的游戏编程可以起到很好的启发...
网络版本的中国象棋服务器源代码,实现象棋的基本功能,对大家的游戏编程可以起到很好的启发-network version of the Chinese chess server source code, chess achieve the basic functions of the game programming we can play good source of inspiration
- 2022-05-13 09:28:05下载
- 积分:1
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Guessnumber
猜数字游戏 游戏说明: 1、游戏开始,电脑随机产生一个数字不重复的四位数。 2、将您猜的数点击OK按钮提交。 3、电脑会将您提交的数与它自动产生的数进行比较,结果显示成"*A*B"。A代表位置正确数字也正确,B代表数字 正确但位置不正确,比如:"2A2B"表示您有2个数字的位置正确且数值也正确,除此以外,您还猜对了2个数字 ,但位置不对。 4、您共有10次机会,在10次内,如果结果为“4A0B”,游戏成功。如果10次里您都没有猜对游戏失败。(Guessnumber: 1, games started, the computer randomly generated a number of non-repetition of the four-digit. 2, would you guess the number of clicks the OK button to submit. 3, the computer will take you to submit a few with it automatically generated a number of comparison, the result is displayed as* A* B . A representative of the location of the correct figure is also correct, B representative of the number of correct but the location is incorrect, such as: 2A2B that you have a two-digit numerical position is correct and also the right, in addition, you guessed it two figures, but wrong location. 4, your opportunity for a total of 10 times in 10 times, if the results of 4A0B , the game successfully. 10 years if you do not have to guess the failure of the game.)
- 2021-03-22 08:19:17下载
- 积分:1
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取得主机名称与各项网络服务的程序代码
取得主机名称与各项网络服务的程序代码-To obtain the host name and the network services program code
- 2022-03-05 13:38:58下载
- 积分:1
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5大IO模型之二:overlap模型,介绍overlap网络io的一般流程。
5大IO模型之二:overlap模型,介绍overlap网络io的一般流程。-five large IO model bis : overlap model, introduced overlap network io the general process.
- 2022-04-18 09:30:46下载
- 积分:1
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_C_
说明: 一个月挑战C++ 电子书C++教学
适合新手入门学习(Month challenge C++ C++ books for beginners to learn teaching)
- 2010-04-23 20:26:07下载
- 积分:1
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收发电子邮件-e-mail
- 2022-07-01 03:04:09下载
- 积分:1