Semester_Thesis_Janev_2009

A wonderful ica toollbox about blind source separation for the beginners

基于matlab来描述静电场的分布，基于matlab描述电偶极子的分布。(Matlab-based to describe the distribution of electrostatic field, matlab-based description of the distribution of electric dipole.)

波束空间MUSIC算法（music算法中的一种），对多个不同方向的信号进行入射角估计，里面包含了m文件、理论推导、仿真结果以及相关讨论。(Beam space MUSIC algorithm (a) the music algorithm, a number of different directions, the signal of the angle of incidence is estimated, which contains m documents, theoretical analysis, simulation results and related discussions.)

Solving Nonlinear Equations using Newton

matlab的m文件，讲述的是pem燃料电池的电流动态仿真，其中还分为m层中有损伤和没有损伤，对研究燃料电池的电流动态者很有用。(matlab m files, about pem fuel cell current dynamic simulation, which is divided into m layer damage and no injuries, the current dynamics of the fuel cell research useful.)

内容完整且每章相对独立；是一本简明的MATLAB参考书，既适用于初学者，也适用于高级MATLAB用户。对MATLAB与FORTRAN、C等语言结合的描述更是所有MATLAB书籍中少有的一大特色。(The contents of each chapter is relatively complete and independent it is a simple MATLAB reference books, both for beginners, but also to high-level MATLAB users. Of MATLAB and FORTRAN, C and other languages with a description of all MATLAB books is a major feature of the few.)

说明：  MATLAB的中文帮助文档，让那些不愿意看英文的朋友们，简单明了的学习MATLAB(MATLAB help documentation in Chinese, English, for those who do not want to see friends, to learn simple MATLAB)

一篇关于能量有效和QoS的无线传感器网络协议论文Energy efficient and QoS based routing protocol for wireless sensor networks(Energy efficient and QoS based routing protocol for wireless sensor networks)

说明：  Matlab code for simulation of PSO (Particle Swarm Optimization)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)