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amplitudefrequency
用MATLAB使信号x(t)产生函数,并显示信号的幅频特性曲线(Using MATLAB to signal x (t) generating function, and displays signal amplitude-frequency characteristic curve)
- 2010-11-21 10:49:15下载
- 积分:1
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bianshi
利用递推最小二乘法(Rls)的过程模型辨识,(The use of recursive least squares (Rls) the process of model identification,)
- 2009-05-22 10:43:01下载
- 积分:1
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fwgn
FWGN信道模型MATLAB编程,对研究信道建模很有帮助(FWGN channel model)
- 2011-05-17 11:40:39下载
- 积分:1
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HPCtesting
高性能计算机的性能测试文案,介绍了曙光计算机的相关测试工作。(High-performance computer performance test copy, describes the work of the dawn of the computer-related tests.)
- 2015-01-29 16:25:47下载
- 积分:1
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Time-Domain-codes
有限时域差分算法计算Mie散射有限时域差分算法计算Mie散射(Finite-difference time-domain algorithm to calculate the Mie scattering)
- 2013-05-16 21:49:45下载
- 积分:1
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MATLAB--communication
Matlab通信仿真及应用源码,很详尽,也可以作为matlab通信初学者运用(Matlab of Communication Simulation and application source code, very detailed matlab communication beginners to use, but also can be used as)
- 2012-12-03 17:26:09下载
- 积分:1
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BP
说明: 本程序经过本人的调试运行,能够实现对手写数字的识别,成功率达 80(After I debug this program to run, to realize the handwritten digit recognition, the success rate of 80)
- 2010-08-01 11:22:15下载
- 积分:1
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Power-spectrum-estimation
功率谱估计
信号为两个正弦信号加高斯白噪声,各正弦信号的信噪比均为10dB,长度为N,信号频率分别为 和 ,初始相位 ,取 , 取不同数值:0.3,0.25。 为采样频率。分别用Levinson递推法和Burg法进行功率谱估计,并分析改变数据长度、模型阶数对谱估计结果的影响。(Power spectrum estimation signal into two sinusoidal signals applied Gaussian white noise, the SNR of each sinusoidal signal are 10dB, a length of N, respectively, and the signal frequency, initial phase, take, take different values: 0.3,0.25. Is the sampling frequency. Levinson recursive method were used and Burg method for power spectrum estimation, and change the length of the data analysis, the impact on the estimation model order spectrum.)
- 2015-03-23 10:48:42下载
- 积分:1
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4.Unsharp-Masking
Use Laplacian filter to enhance the picture.
- 2013-01-14 16:14:41下载
- 积分:1
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niudun
用牛顿法解决非线性规划问题,解决问题所需时间少,能提高效率,但须具有二阶导数(Newton' s method to solve nonlinear programming problems, less time, and can improve the efficiency needed to solve the problem, but must have a second derivative)
- 2013-04-08 18:20:44下载
- 积分:1