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zikong
判断系统上升时间,峰值时间,超调量和调整时间。《自动控制》清华出版社的课后编程题目。(Determine the system rise time, peak time, overshoot and time to adjust. )
- 2020-12-18 14:39:11下载
- 积分:1
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Matlab_junheng
matlab 强大的信号仿真功能结合VC编程混编分析数字均衡器的设计要求对各种音频信号进行处理
(matlab simulation capabilities combined with powerful signal analysis VC programming mixed digital equalizer design requirements of the various audio signal processing)
- 2011-02-01 13:19:36下载
- 积分:1
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knnsearch
寻找距离某一点最近的几个点,返回对应的点的位置及距离该点的距离(Find a few points closest to a given point , returns the corresponding location of the point and the distance from the point)
- 2020-10-25 15:10:01下载
- 积分:1
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fourier
One dimensional interpolation Fourier transform to realize data sampling
- 2015-01-27 21:01:13下载
- 积分:1
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Sand-pile
一堆沙子的横截面,可以使用 Margolus 型邻居仿真,但运动规则不同。
规则:
元胞有 2 个状态。状态= 0 是空的,状态= 1 代表沙子。
在任何时间步长,一个粒子,可以在2x2 块中向着底部运动。可能运动如下
所示。墙壁和底部将阻止粒子继续运动。
为了让该运动略有随机性,我亦补充说一项规则,有时处于下落状态的两个元胞还旋转,直到所有的动作都完成。(Cross-section of a pile of sand, you can type using the Margolus neighborhood simulation, but the movement rules are different. Rules: There are two cellular states. State = 0 is empty, state = 1 for sand. At any time step, a particle can be in the 2x2 block toward the bottom of the movement. May exercise the following. Walls and bottom to prevent the particles continue to campaign. To make the campaign a little random, I also added a rule, sometimes in the falling state of the two cell also rotate until all actions are completed.)
- 2011-06-30 20:01:06下载
- 积分:1
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ClassificadorNN.m
ClassificadorNN for traffic signals
- 2013-03-11 08:03:58下载
- 积分:1
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ATTENUATIONS
matlab file for cample bozorgnaia 2004 attenuation code
- 2013-11-07 16:31:51下载
- 积分:1
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LMSmatlabdsp
lms的matlab算法,dsp源程序,包含效果图(lms algorithm matlab, dsp source code, including renderings)
- 2013-12-28 11:08:51下载
- 积分:1
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Numerical-method-solve-equations
数值方法解方程组AX=B(LU分解),过程分3步,首先,分解系数矩阵A=LU,然后,解LY=B,最后再求UX=Y 另一种是直接求解的(2.1)(Numerical method to solve the equations AX = B (LU decomposition), 3 step process, first of all, the decomposition of the coefficient matrix A = LU, then, Xie LY = B, and finally seek UX = Y another directly solving (2.1 ))
- 2012-10-02 15:34:09下载
- 积分:1
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continousbeam
结构力学连续梁节点弯矩求解,用于求解静定或者超静定梁的内力。(Structural Mechanics continuous beam bending moment for solving the node for the solution of statically determinate or statically indeterminate beam internal forces.)
- 2020-07-03 11:00:02下载
- 积分:1